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2 years ago

What is the coefficient of the second term in this expression?9–6w–5y

Mathematics

1 answer:

Ber [7]2 years ago

4 0

Answer:

The coefficient of the second term in this expression is 6.

Step-by-step explanation:

A coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression. There are three terms in this expression (9, 6w, and 5y), and the coefficient of the second term is 6.

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Solve this system of equations using the substitution method<br> y = 2x + 17<br> y = 6x - 3

guapka [62]

Step-by-step explanation:

well, as you can witness both of the equations are equal to y, so you're free to reckon that they are equal as well

$6x - 3 = 2x + 17 = = = > \\ 4x = 20 = = = > x = 5 \: and \: \\ y = 6(5) - 3= = = > y = 27$

5 0

2 years ago

In a sports equipment locker, there are 81 balls and 45 baseball mitts. Write the ratio of balls to baseball

Romashka-Z-Leto [24]

Answer: 9:5

Step-by-step explanation:

81:45 I first just divided them both by three and got 27:15 then they were both divisible by 3 so then I got 9:5

6 0

3 years ago

Is (4, -2) the solution of the system of equations shown

Advocard [28]

No, because if you substitute (4, -2) into x and y in each equation, they are not the same as the value on the right side of the equation.

2(4) + 4(-2) = - 2

8 + -8 = -2

0 = -2 <---- this is not correct.

-4(4) + -2 = -14

-16 + -2 = -14

-18 = -14 <----- this is not correct.

8 0

2 years ago

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

2 years ago

If f(x) = -3x4 - 2x3 + 3x2, and g(x) = 3x4 - 4x3 + x2 then f(x) + g(x) =

Alex_Xolod [135]

I'm assuming the the numbers coming after the variables are meant to be exponents, and if I'm wrong just let me know

-3x^4 - 2x^3 + 3x^2 + 3x^4 - 4x^3 + x^2, rearrange to have like terms in order
-3x^4 +3x^4 - 2x^3 - 4x^3 +3x^2 + x^2, now simplify
0 -6x^3 + 4x^2

6 0

3 years ago