Let us assume number of toppings = n
Total weight of sundae = s
Quantity of Ice cream = 2 kilograms.
We need to discribe the total weight of the special sundae in kilograms by an inequality.
The sundae contains ice cream and number of toppings.
So the total weight of the sundae will be greater than the total weight of ice cream and number of toppings, because there would be some weight of the packing.
Therefore,
The total weight of the sundae > total weight of ice cream + weight of toppings.
s > 2 + n.
Where, s is the total weight of the sundae and n is the weight of toppings. I hope this was helpful!. :)
Explanation:
answer my latest question I beg you
These people are referred to as the <u>discouraged workers.</u>A person who is eligible for employment and can work but is unemployed currently and has not attempted to find employment in the last four weeks
Explanation:
Discouraged workers are the individuals who is eligible for employment and can work but is unemployed currently and had not made any attempt to find employment in the last four weeks.
For example: Young graduates,senior citizens.
Discouraged workers are not considered as a part of the labour force and are not counted in most official unemployment rates.
<u>These are people who were not in the labor force, although they wanted work and were available for it and had looked for jobs at some point in the previous 12 months. They were not counted as unemployed because they had not actively searched for work in the 4 weeks preceding the survey.</u>
If unemployed workers become discouraged, the measured unemployment rate will fall
Speed= distance divided by time so s=d/t
first find the individual speeds during each running segment. we get
s=4.0/32=1/8 km per min
s=2.0/22=1/11 km per minute
s=1.0/16=1/16 km per minute
now we take the average. the person jogged a TOTAL of 7.0 km in a TOTAL 70 minutes. so on average, they jogged 7.0/70=1/10 km per minute
Answer:

square both sides:

solve the roots:

take a cube root on both sides:
![\sqrt[3]{ {x}^{3} } = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
solve the cube root:
