Answer:
Option B
Step-by-step explanation:
Given that cosθ = 
Since, θ is an angle in quadrant II therefore, cosine value is negative
Now we will find the tangent ratio from the given triangle.
tanθ = 
From the given triangle,
By applying Pythagoras theorem in the given right triangle,
AC² = AB² + BC²
AB² = 10² - 3²
= 100 - 9
= 91
AB = √91
tanθ = 
Now, tanθ = 
Since, θ is in second quadrant therefore, tangent of the angle will be negative.
tanθ = 
Option B is the answer.
Answer:
See below
Step-by-step explanation:
<em>Quadratic function is in general form of:</em>
- <em>y = ax^2 + bx + c</em>
<em>The function has a minimum if a > 0 and maximum if a < 0</em>
<em>The minimum or maximum point is a vertex of the graph</em>
- <em>A vertex is the point x = -b/2a</em>
<em>When b = 0, the min or max point equals to value of c.</em>
- 33. It has maximum of -1
- 34. It has minimum of 7
- 35. It has minimum at x = - 8/4 = -2
f(-2) = 2*(-2)^2 + 8(-2) + 7 = 8 - 16 + 7 = - 1
- 36. It has maximum at x = -18/2(-3)= 3
g(3) = -3*3^2 + 18*3 - 5 = -27 + 54 - 5 = 22
- 37. It has minimum at x = - 6/(2*3/2) = - 2
f(-2) = 3/2*(-2)^2 + 6(-2) + 4 = - 6 - 12 + 4 = - 14
$7
30 divided by 6 is 5, then you take that 35 and divide it by the 5and you will end up with $7
Acute Angles measure below 90°
So this angle would be an acute angle
I think it is 6y + 5x^(4) - 7x
