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2 years ago

FREE BRAIN!! TO THE FIRST PERSON

Mathematics

2 answers:

Vladimir79 [104]2 years ago

8 0

Answer:

yeet ttttt

Step-by-step explanation:

...... ......

yan [13]2 years ago

3 0

Answer:

<h2><em>Yay!!!!!! Thanks a lot mate....</em><em>♡</em></h2><h2><em>Pls give Brainliest!</em></h2>

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Please help with this question

Eddi Din [679]

Answer:

92°

Step-by-step explanation:

We can say that the angle that is of x degrees is an inscribed angle because its vertex is on the circle and its sides are made up of rays. When you have an inscribes angle, it measures exactly half the angle it intercepts. In this case that angle is 184°. So, because of this we can say:

x = 184° / 2

x = 92°

6 0

3 years ago

Diana and Tom buy two cell phones. The phone numbers assigned to each are consecutive integers with a sum of 11,107,273. If the

lilavasa [31]

Answer:

Is this the full question?

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=24x%5E%7B2%7D%2Bbx%5E%7B2%7D%20%3D25x%5E%7B2%7D" id="TexFormula1" title="24x^{2}+bx^{2} =25x^{

Liula [17]

Answer:

x = 0

Step-by-step explanation:

Subtract 25x^2 from both sides

24x^2 + bx^2 - 25x^2 - 25x^2

Simplify

bx^2 - x^2 = 0

Factor bx^2 - x^2: x^2(b - 1)

bx^2 - x^2

Factor out common term x^2

= x^2 (b - 1)

x^2(b - 1) = 0

Using the Zero Factor Principle: If ab = 0 then a = 0 or b = 0

x^2 = 0

Apply rule x^n = 0 x = 0

x = 0

8 0

2 years ago

A tank contains 30 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min

Dmitry [639]

At any time $t$ (min), the volume of solution in the tank is

$500\,\mathrm{gal}+\left(5\dfrac{\rm gal}{\rm min}-5\dfrac{\rm gal}{\rm min}\right)t=500\,\mathrm{gal}$

If $A(t)$ is the amount of salt in the tank at any time $t$ , then the solution has a concentration of $\dfrac{A(t)}{500}\dfrac{\rm lb}{\rm gal}$ .

The net rate of change of the amount of salt in the solution, $A'(t)$ , is the difference between the amount flowing in and the amount getting pumped out:

$A'(t)=\left(5\dfrac{\rm gal}{\rm min}\right)\left(\left(2+\sin\dfrac t4\right)\dfrac{\rm lb}{\rm gal}\right)-\left(5\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{A(t)}{50}\dfrac{\rm lb}{\rm gal}\right)$

Dropping the units and simplifying, we get the linear ODE

$A'=10+5\sin\dfrac t4-\dfrac A{10}$

$10A'+A=100+50\sin\dfrac t4$

Multiplying both sides by $e^{10t}$ allows us to identify the left side as a derivative of a product:

$10e^{10t}A'+e^{10t}A=\left(100+50\sin\dfrac t4\right)e^{10t}$

$\left(e^{10}tA\right)'=\left(100+50\sin\dfrac t4\right)e^{10t}$

$e^{10t}A=\displaystyle\int\left(100+50\sin\dfrac t4\right)e^{10t}\,\mathrm dt$

Integrate and divide both sides by $e^{10t}$ to get

$A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+Ce^{-10t}$

The tanks starts off with 30 lb of salt, so $A(0)=30$ and we can solve for $C$ to get a particular solution of

$A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+\dfrac{32,220}{1601}e^{-10t}$

6 0

3 years ago

Heeelp<br> . Can someone please answer this to meee ? <br><br><br><br><br><br><br> .

lilavasa [31]

Answer:

If f(x)=g(x), the solution is x=-2

Step-by-step explanation:

We are given:

$f(x)=3x+3\\g(x)= (-1/2)x-4$

We need to find the solution if f(x)=g(x)

Now solving for f(x)=g(x)

$f(x)=g(x)\\3x+3=(-\frac{1}{2}x)-4\\3x+3=-\frac{1}{2}x-4\\3x+\frac{1}{2}x=-4-3\\\frac{3x*2+x}{2}=-7\\\frac{6x+x}{2}=-7\\\frac{7x}{2}=-7\\x=-7*\frac{2}{7}\\x=-2$

If f(x)=g(x), the solution is x=-2

7 0

3 years ago