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djyliett [7]
3 years ago
6

Write 81.4 as a fraction.

Mathematics
2 answers:
Maslowich3 years ago
7 0
407 over 5 but it also has to be simplified
Sveta_85 [38]3 years ago
4 0
It is 81.4 over 1000
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George deposited $750.00 into an account that earns 7% interest which is compounded 2 times per year. How much money will George
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If I did my math correctly I believe your answer will be C. :)
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Read 2 more answers
How do i solve this question
frozen [14]
\bf \begin{cases}
h(x)=(f\circ g)(x)\\
h(x)=\sqrt{x+5}\\
f(x)=\sqrt{x+2}
\end{cases}\\\\
-------------------------------\\\\
(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus
\\\\\\
\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore
\\\\\\
\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\
g(x)+2=x+5\implies g(x)=x+5-2\implies \boxed{g(x)=x+3}
8 0
3 years ago
Math help please <br><br> Thanks <br> A lot
babunello [35]

Answer:  

2 hours:  3968  <u>[I don't understand the $ sign in the answer box]</u>

At midnight:  12137

Step-by-step explanation:

The bacteria are increasing by 15% every hour.  So for every hour we will have what we started with, plus 15% more.  

The "15% more" can be represented mathematically with (1 + 0.15) or 1.15.  Let's call this the "growth factor" and assign it the variable b.  b is (1 +  percent increase).

Since this per hour, in 1 hour we'll have (3000)*(1.15) = 3450

At the end of the second hour we're increased by 15% again:

(3450)*(1.15) = 3968.

Each additional hour add another (1.15) factor,  If we assign a to be the starting population, this can be represented by:

P = a(1.15)^t for this sample that increase 15% per hour.  t is time, in hours.  

If a represents the growth factor, and P is the total population, the general expression is

P = ab^t

Using this for a = 3000 and b = 1.15, we can find the total population at midnight after starting at 2PM.  That is a 10 hour period, so t = 10

P = (3000)*(1.15)^10

P = 12137

8 0
2 years ago
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