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Maksim231197 [3]
3 years ago
12

1. What is the solution of n² – 49 = 0? (1 point)

Mathematics
2 answers:
maks197457 [2]3 years ago
8 0

Answer:

1. n=\pm7

2. x=\pm7i[tex]3.[tex]\pm 12x =a

4. 22

Step-by-step explanation:

1. n^2 - 49 = 0

n^2 =49

n= \sqrt{49}

n=\pm7

2. x^2+64 = 0

x^2 =-64

x= \sqrt{49}

x=\pm7i[tex]3. Area of square = [tex]a^{2}

Where a is the side

We are given an area o square = 144x^{2}

So, 144x^{2}=a^{2}

\sqrt{144x^{2}}=a

\pm 12x =a

4. We are given that the solution of quadratic equation -9 and 9

So, equation becomes:

(x+9)(x-9)=0

x^2- 81=0

So, in the given equation x^2 + z = 103

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

x^2 + 22 = 103

x^2 + 22 -103=0

x^2 -81=0

Thus the value of z is 22

Lubov Fominskaja [6]3 years ago
3 0
1. The solution of the equation is the third option.
2. The equation has no real solution because the answers are both imaginary numbers.
3. The side length of a square with an area of 144x² is 12x.
5. The value of z so that 9 and -9 are both solutions is equal to 22.
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