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Phantasy [73]
2 years ago
7

Does anyone know the answer?

Mathematics
1 answer:
kolezko [41]2 years ago
8 0

Answer:

Part A: 9.75x > 195

Part B: x > 20

Step-by-step explanation:

Let's say Mark works for x hours. For each hour he works, 9.75 dollars are added to Mark's salary. Therefore, for 1 hour, he gets $9.75, for 2 hours, he gets $9.75 + $9.75 = $9.75 * 2 = $19.50, and for x hours, he gets $9.75 * x as his salary.

We want his salary to be more than $195, so we have $9.75 * x (his salary) > $195, which can be written as 9.75x > 195

divide both sides by 9.75 to solve for x

x > 20

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Uestion 2 (1 point)
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-The probability of choosing a meat dish is equal to the probability of choosing a pasta dish or a soup(P(meat)\neq P(pasta)+P(soup))

Step-by-step explanation:

Given that the number of events is 25 and 13 are meat dishes, 8 are pasta dishes, and 4 are soups.

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#find probability of each event:

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P(meat)\neq P(pasta)\neq P(soup)

Hence, the FALSE choice is:The probability of choosing a meat dish is equal to the probability of choosing a pasta dish or a soup.

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Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
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