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fredd [130]
3 years ago
13

Find the lines of symmetry for each shape. Select all that apply.

Mathematics
1 answer:
nadezda [96]3 years ago
8 0

4 lines of symmetry

c. n because it separates the shape on the middle

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-x + 5y = 13<br>x - y = 15​
aivan3 [116]

Answer:

x-y-15=15-15

x-y-15=0

hope this helps :)

3 0
3 years ago
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A rectangle has a length of (x+10) centimeters and a width of x centimeters. If the perimeter is 32 centimeters, what is the len
I am Lyosha [343]

Given:

Length of rectangle = (x+10) cm

Width of the rectangle = x cm

Perimeter = 32 cm

To find:

The length of the rectangle.

Solution:

We know that,

Perimeter=2(l+w)

Where, l is length and w is width.

Substituting the values, we get

32=2((x+10)+x)

32=2(2x+10)

32=4x+20

Subtract 20 from both sides.

32-20=4x

12=4x

Divide both sides by

3=x

So, the length is

3+10=13

Therefore, the length of the rectangle is 13 cm.

7 0
3 years ago
Help shaded parts need answers
Andrej [43]

Answer:

? i cant understand this!!!!!!!

Step-by-step explanation:

4 0
3 years ago
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
Find the area of the figure, 5 in. 2 in. 4 in. 5 in.​
bearhunter [10]
I don’t know sorry I’m on this app because I need help myself
8 0
3 years ago
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