Let x be the volume (liters) of pure (at 100%) acid needed
Let y be the volume (liters) of the other acid (at 10%) needed
The final solution will be:
a) x+ y = 63 liters, AND their respective concentration in acid: is
100% x & 10% :y that will generate 63 liters at 20%
b) x +0.1 y = 63x 0.2 = 12.6
Let's solve this system of 2 equations:
x + y =63
x + 0.1 y = 12.6
Solving it will give you:
x= 7 liters at 100%
y = 56 liters at 10%
Answer: i have never did a math problem like this before because i'm only in the 2nd semester of 7th grade but i will try, i think it is 2090
Step-by-step explanation: 5000 divided by 2 = 2500. then you do 2500-410. 2500-410= 2090. (i hope this will help you and sorry if i did it wrong) :)
(0,0) and (6,0)
First we subtract 18x from both sides
3x²-18x=0
Factor out a 3x
3x(x-6)=0
This means that x is either 0 or 6
Answer:
hey dude, The formula is (x-y)³=x³-3x²y+3xy²-y³.