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kicyunya [14]
2 years ago
13

Does someone know this answer. My teacher has a hard time solving it .

Mathematics
2 answers:
sukhopar [10]2 years ago
7 0

\sqrt{289}= \\ \sqrt{17\times17}= \\ \sqrt{{17}^{2}}=17

ahrayia [7]2 years ago
4 0

SOS

Answer: \sqrt{289}=17

\mathrm{Factor\:the\:number:\:}\:289=17^2\\=\sqrt{17^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\=17

<em>Hope this helps!!!</em>

<em>Sofia</em>

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DerKrebs [107]

we are given

differential equation as

y'''-9y''+20y'=0

we are given

y=e^{rx}

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

y'=re^{rx}

Second derivative is

y''=r*re^{rx}

y''=r^2e^{rx}

Third derivative is

y'''=r^2*re^{rx}

y'''=r^3e^{rx}

now, we can plug these values into differential equation

and we get

r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0

now, we can factor out common terms

e^{rx}(r^3 -9r^2 +20r)=0

we can move that term on right side

(r^3 -9r^2 +20r)=0

now, we can factor out

r(r^2 -9r +20)=0

r(r-5)(r-4)=0

now, we can set them equal

r=0

r-5=0

r=5

r-4=0

r=4

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r=0,4,5...............Answer

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3 years ago
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The length of a shadow of a building is 30 m. The distance from the top of the building to the tip of the shadows is 36 m. Find
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Answer:

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2 years ago
Raquel has created a program for a robot. The robot travels 10 meters and stops. The program is designed for wheels that are 2.5
Grace [21]

Answer:

Raquel should adjust the number of rotations  to 115.81 rotations

Step-by-step explanation:

step 1

Find the circumference of the wheels that are 2.5 cm in diameter

The circumference is equal to

C=2\pi r

we have

r=2.5/2=1.25\ cm

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substitute

C=2(3.14) (1.25)

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step 2

Find the number of rotations

Divide 10 meters by the circumference

10\ m=1,000\ cm

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step 3

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The circumference is equal to

C=2\pi r

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step 4

Find the number of rotations

Divide 10 meters by the circumference

10\ m=1,000\ cm

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2 years ago
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