Question

Does someone know this answer. My teacher has a hard time solving it .

Answer 1

$\sqrt{289}= \\ \sqrt{17\times17}= \\ \sqrt{{17}^{2}}=17$

Answer 2

SOS

Answer: $\sqrt{289}=17$

$\mathrm{Factor\:the\:number:\:}\:289=17^2\\=\sqrt{17^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\=17$

Hope this helps!!!

$Sofia$