The reactions of glycolysis are made up of ten steps, out of the ten step three are irreversible, this is because, these reactions have large negative free energies The three steps that are irreversible are:
1. Phosphorylation of glucose.
2. Phosphorylation of glucose 6 phosphate and
3. Transfer of phosphate from phosphoenolpyruvate to ADP.
Answer:
Co-dominance because he expresses both of the alleles simultaneously
Explanation:
The ABO blood group system is used by humans. This blood group type is controlled by multiple alleles. Alleles A and B are both dominant over allele O but are co-dominant. Co-dominance is a type of inheritance pattern in which two alleles of a gene both express themselves i.e. neither is recessive.
This is the case of this family whose parents have a genotype of AO (blood type A) and BO (blood type B) respectively. The children have blood types A, B, and AB. However, the child with genotype AB possesses both the A and B allele, which are both expressed in his blood group (phenotype), hence, it can be said that the child is exhibiting CO-DOMINANCE for the blood group trait.
The correct answer is Solid.
Answer:
movement corridors
Explanation:
Animal movement corridors are elongated, naturally vegetated parts of the landscape used by animals to move from one habitat to another.
<span>microtubules and microfilaments </span>
