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Tatiana [17]
3 years ago
8

A group of seven students brought enough peppermint candy to share equally among themselves during a computer lab meeting. which

could be the number of pieces of peppermint candy they bought
A: 64
B: 56
C: 38
D: 27

Mathematics
1 answer:
otez555 [7]3 years ago
4 0

Answer:

56

Step-by-step explanation:

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6 0
3 years ago
Solve the system of linear equations. <br> −8x+5y=26<br> 9x−3y=−3
Sloan [31]

Answer: x = 3 and y = 10

Step-by-step explanation:

-8x + 5y = 26     .................. equation 1

9x - 3y = -3          ................ equation 2

Solving the system of linear equations by elimination method.

The means we have to make the coefficient of one of the variable the same in order to eliminate the variable first.

Let us eliminate the variable y first , this means we will multiply equation 1 by 3 and multiply equation 2 by 5. Doing this , we have

-24x + 15y = 78      ............. equation 3

45x - 15y = -15     ................ equation 4

Now that we have the same coefficient , we have to check their signs , if the have the same signs , we will subtract , that is , if both are having positive signs , we will subtract , if both have negative signs , we will also subtract but if their signs differ we will add. Following this rule and considering the equations above , the coefficients of y have different signs , so we will add equation 3 and equation 4 , so we have:

21x = 63

x = 63/21

x = 3

Substitute x = 3 into equation 1 or equation 2 to get the value of y , using equation 2 , we have

9x - 3y = -3

9(3) - 3y = -3

27 - 3y = -3

27+3 = 3y

30 = 3y

30/3 = y

Therefore y = 10

Therefore : x = 3 and y = 10

8 0
4 years ago
Find the area of a traingle given that the base is 19.5cm and height is 8 4/5cm.
Phoenix [80]

Answer:

85.6cm

Step-by-step explanation:

Area of a triangle =1/2*b*h

Where base=19.5cm while the height is 8 4/5 = 8.8

Area = 1/2 * 19.5cm * 8.8cm

Area = 171.6cm/2

Area=85.6cm

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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This can also be verified plugging in the values of x=0,y=-7 and x=7,y=0. The only equation which satisfies these points in Equation B. These points have been chosen as they're the intercepts of this plot.

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