Answer:
J. -13-18
Step-by-step explanation:
J will give the value -31
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
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A+b+c=28x+40=180
—>28x=140
—>x=140/28=5
c=9x-3
—>c=42
Answer:
D: 0.75

Step-by-step explanation:
<u>Explanation</u>:-
<u><em>Independent events:</em></u>
If the occurrence of the event 'B' is not effected by the occurrence or non- occurrence of the event 'A' then the event 'B' is said to be independent of 'A'
or
<em>The two events are independent if the incidence of one event is not affect the probability of other event.</em>
<em>P(A∩B) = P(A) P(B)</em>
Given data A and B are independent events
Given data

we know that A and B are independent events are
P(A∩B) = P(A) P(B)

Now calculation we get

<u><em>Final answer:</em></u>-
