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2 years ago

Solve the compound inequality. -14< 3x+1 ≤ 13 Graph the solution on the number line.

Mathematics

1 answer:

Zolol [24]2 years ago

8 0

Answer:

(1) 2x - 6 < - 14

(2) 2x + 3 < 1

Explanation:

(1) 2x - 6 < -14 -> 2x < - 8 -> x < - 4

(2) 2x + 3 < 1 -> 2x < -2 --> x < -1

Compound solution set: x < - 4

==========|-4----------|-1-------|0----------------

Step-by-step explanation:

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$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

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$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

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