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3 years ago

factor out the gcf of the expression. express you answer as the product of the gcf and remaining factor

Mathematics

1 answer:

ser-zykov [4K]3 years ago

3 0

son varias respuestas mijo

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When you play darts, you know three darts at the board and add the scores. Bristoe and Clancy are practising. Here are the score

Alja [10]

The person who has a better average will be Clancy.

The person who has more varied scores is Bristoe.

<h3>How to calculate the average??</h3>

Bristoe - 18,32,26,53,5,29,41,15,85,9,44,28,100,37,55. The average will be the addition of the numbers as dividing by 15. This will be:

= 577/15

= 38.47

Clancy - 41,26,33,51, 26,29,60,45,60,19,42,36.

Average= 468/12

= 39

The person who has a better average will be Clancy.

The person who has more varied scores is Bristoe.

Learn more about average on:

brainly.com/question/6504879

#SPJ1

8 0

1 year ago

A: 10<br> B: 70<br> C: 30<br> D: 90

tatuchka [14]

A. 10

because 80 - 10 = 70 & 90 - 2(10) = 70

3 0

3 years ago

Matthew is half as old as Alan. If the sum of their ages is 54, find their ages.

kompoz [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

I need help with this. screenshot attached

CaHeK987 [17]

Answer: 7/5

rise/run
= (7-0)/(8-3) = 7/5

7 0

4 years ago

Using the order of operations, what should be done first when evaluating this expression?

Nastasia [14]

Answer:

$-\frac{16}{17}\\-0.94117$

Step-by-step explanation:

$\frac{-\frac{1}{2}}{\frac{2\left(9+3\right)-4-3}{4\left(8\right)}}\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=\frac{-\frac{1}{2}}{\frac{2\left(9+3\right)-4-3}{4\cdot \:8}}\\\frac{2\left(9+3\right)-4-3}{4\cdot \:8}=\frac{17}{32}\\\frac{2\left(9+3\right)-4-3}{4\cdot \:8}\\2\left(9+3\right)-4-3=17\\2\left(9+3\right)-4-3\\2\left(9+3\right)=24\\2\left(9+3\right)\\\mathrm{Add\:the\:numbers:}\:9+3=12\\=2\cdot \:12\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:12=24\\=24-4-3$

$\mathrm{Subtract\:the\:numbers:}\:24-4-3=17\\=\frac{17}{4\cdot \:8}\\\mathrm{Multiply\:the\:numbers:}\:4\cdot \:8=32\\=\frac{17}{32}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}\\=-\frac{\frac{1}{2}}{\frac{17}{32}}\\\mathrm{Divide\:fractions}:\quad \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c}\\=-\frac{1\cdot \:32}{2\cdot \:17}\\Refine\\=-\frac{32}{2\cdot \:17}\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:17=34\\=-\frac{32}{34}$

$\mathrm{Cancel\:the\:common\:factor:}\:2\\=-\frac{16}{17}\\\mathrm{Decimal:\quad }\:-0.94117$

3 0

3 years ago