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3 years ago

2. Both the populations of the Candy Kingdom and the Fire Kingdom are in decline; their populations

Mathematics

1 answer:

VMariaS [17]3 years ago

4 0

Answer:2. Both the populations of the Candy Kingdom and the Fire Kingdom are in decline; their populations

since 2010 are given by the functions below:

Cit) 1000 - 500

F(t) = 2500 - 1000

Will their populations ever be equal? If so, when will that happen and what will that population be?

Otherwise, briefly explain why their populations will never be equal.

Step-by-step explanation:

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Brainliest if correct! Please explain how this is done!

Korvikt [17]

The value of csc C in fraction and in decimal form is as follows:

csc C = 5 / 3

csc C = 1.66666666667

Using trigonometric ratio,

secant A = 1 / cos A = hypotenuse / adjacent

Therefore,

sec A = 5/3

sec A = 1 / cos A

cos A = adjacent / hypotenuse

cos A = 3 / 5

A = cos⁻¹ 0.6

A = 53.1301023542

Therefore,

∠A = 53°

∠B = 90°

∠C = 180 - 143 = 37°

cosec C = 1 / sin C = hypotenuse / opposite

cosec C = 5 / 3

learn more about trigonometry here: brainly.com/question/25942962?referrer=searchResults

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2 years ago

Jerome tries to find the value of the expression 3 - 6 + 5 by first applying the commutative property he rewrites the expression

Lana71 [14]

Wrong in sign change

How?

In commutative law the sign doesn't change whenever it is applied.

Thus

$\\ \sf{:}\implies 3-6+5$

$\\ \sf{:}\implies 3\underline{+5-6}$

$\\ \sf{:}\implies 8-6$

$\\ \sf{:}\implies 2$

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2 years ago

( − 6 u 9 − 14 u 3 ) + ( − 13 u + 2 u 9 )

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Step-by-step explanation:

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2 years ago

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Solve the inequality –1 > –2(x – 4) – 5(4x – 7).

Ksivusya [100]

Answer:

$x > 2$

Step-by-step explanation:

$–1 > –2(x – 4) – 5(4x – 7)$

$–1 > –2x + 8 –20x + 35$

$–1 > - 22x + 43$

$- 1 - 43 > - 22x$

$- 44 > - 22x$

$\frac{ - 44}{ - 22} < \frac{ - 22x}{ - 22}$

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3 years ago

What is the square root of -2i?

Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of $z=0-2i$ . First, convert from Cartesian to polar form:

$r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2$

$\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}$

$z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})$

Next, use the formula $\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]$ where $\displaystyle k=0,1,2,...\:,n-1$ to find the square roots:

When k=1

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]$

$\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i$

When k=0

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i$

Thus, the square roots of -2i are 1-i and -1+i

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2 years ago