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Tanya [424]
3 years ago
15

Philip Schofield bench presses 200N over a distance of 0.5m. calculate the work done

Mathematics
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

100J

Step-by-step explanation:

work done = force x distance

                  = 200 x 0.5

                  = 100J

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Does x equal if the problem is negative x -4x - 7 equals 5 negative 2X
Sphinxa [80]

Answer:

X = - 4

Step-by-step explanation:

Given in problem

- x -4x - 7 = 5 -2x

Or, -5x - 7 = 5- 2x

Or, -5x + 2x = 5 + 7

Or, -3x = 12

Or, x = - \frac{12}{3}

∴ X = - 4    Answer

6 0
3 years ago
Given the volume is 105 inches³ for an 8 pound bowling ball, find the radius of the bowling ball,
mariarad [96]

Answer:

2.92

Step-by-step explanation:

V=\frac{4}{3}\pi r^3 \\ \\ 105=\frac{4}{3}\pi r^3 \\ \\ r^3=\frac{105}{\frac{4}{3}\pi} \\ \\ r=\sqrt[3]{\frac{105}{\frac{4}{3}\pi}}  \\ \\ r \approx 2.92

7 0
1 year ago
Find the oth term of the geometric sequence 7, 14, 28, ...
yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

The ratio of all the adjacent terms is the same and equal to

r=2

now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

6 0
3 years ago
2 Points
Nesterboy [21]

Answer:105

Step-by-step explanation:55-66=74 74times

3 0
3 years ago
Will someone please help me!!! I don’t know the answer to these! I don’t even know if I did them right!
Varvara68 [4.7K]

Answer:

BD = 12 units

AB = 16 units

FG=\sqrt{105}

EC=4\sqrt{10} units

AC=8\sqrt{10} units

Step-by-step explanation:

A circumcenter is the point  where the perpendicular bisectors of a triangle intersect.

This means

  • BD = DC;
  • BF = FA;
  • AE = EC.

Since BC = 24 units, then BD = 12 units (half of BC).

Since FA = 8 units, AB = 16 units (twice FA).

Consider right triangle BGF. In this triangle, BF = 8 units (congruent to FA), BG = 13 units. By the Pythagorean theorem,

FG^2=BG^2-BF^2\\ \\FG^2=13^2-8^2\\ \\FG^2=169-64=105\\ \\FG=\sqrt{105}\ units

Triangles BFG and AFG are congruent right triangles, then BG = AG. In right triangle AGE, GE=3 units, AG=13 units. By the Pythagorean theorem,

AE^2=AG^2-GE^2\\ \\AE^2=13^2-3^2=169-9=160\\ \\AE=\sqrt{160}=4\sqrt{10}\ units

AE = EC=4\sqrt{10}\ units

AC = 2AE=2\cdot 4\sqrt{10}=8\sqrt{10}\ units

5 0
3 years ago
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