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Stolb23 [73]
3 years ago
12

A cooler contains 7 cans of​ soda; 3 ​colas, 3 ​orange, and 1 cherry. Two cans are selected at random without replacement. Find

the probability that at least one can is orange.
Mathematics
1 answer:
erastovalidia [21]3 years ago
3 0
P(NOT Orange)=(4/7)(3/6)

P(NOT Organge)=2/7

P(O>0)=1-2/7

P(O>0)=5/7

So the probability of at least one orange can is 5/7
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Answer:

Both proportions are equivalent.

Step-by-step explanation:

We have been given two proportions \frac{40}{8}=\frac{x}{10} and \frac{x}{40}=\frac{10}{8}. We are asked to find why the solutions to our given proportions are equal.

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You can find these by comparing your equation to the equation y = mx + b, where m is the slope of the line and b is the y-intercept.
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