Ill give u brainiest for correct ans

Mathematics

1 answer:

Marrrta [24]2 years ago

7 0

Answer:

Step-by-step explanation:

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Rewrite 9cos 4x in terms of cos x.

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$\bf \qquad \textit{Quad identities}\\\\
sin(4\theta )=
\begin{cases}
8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\
4sin(\theta )cos(\theta )-8sin^3(\theta )cos(\theta )
\end{cases}
\\\\\\
cos(4\theta)=8cos^4(\theta )-8cos^2(\theta )+1\\\\
-------------------------------\\\\
9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]
\\\\\\
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as far as the previous one on the 2tan(3x)

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$\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[ \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]
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$\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
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Anyone it is almost due help

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Answer: I not super sure, but I think you are supposed to put the equations on each side of the table. Your end result should be 2x to the second -5x-3.

Step-by-step explanation:

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Sara is mixing together a fruit punch for a party. She's made 4 gallons of punch with a mixture of 50% juice. Her mother tells h

Nata [24]

$\bf \begin{array}{lccclll}
&amount(gallons)&juice&\textit{juice amount}\\
&--------&-----&-----\\
\textit{50\% punch}&4&0.50&(4)(0.50)\\
\textit{pure juice}&x&1.00&(x)(1.00)\\
-----&-----&-----&-----\\
mixture&4+x&0.60&(4+x)(0.60)
\end{array}$

notice, that, pure juice is 100% juice, dohhh, thus 100/100 = 1.00
50% is 50/100 or 0.50 in decimal format

so..... whatever those two quantities amount to, that is, the 50% and pure juice, or (4)(0.50) + (x)(1.00)
they will equal the mixture desired 60% juice, or 0.60, namely (4+x)(0.60)

thus (4)(0.50) + (x)(1.00) = (4+x)(0.60)

solve for "x"

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3 years ago