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DedPeter [7]
3 years ago
10

Quick question if I had a problem that was sin x = 18.9/20 =.945 how would I inverse sin of both sides ?

Mathematics
1 answer:
galben [10]3 years ago
6 0

Answer:

The result is about 70.9 degrees

Step-by-step explanation:

Easy for a calculator.  If you're not using a calculator, it's much more tedious!

There is an inverse sine key on your calculator, but you may have to press a key (likely labeled 2nd or INV) first.  The attached image shows a TI-83 display.  To get the inverse sine, I first pressed the yellow 2nd key, then the sin key.

Check MODE first to make sure you're measuring angles in degrees (if that's what you want!).  Some calculators display angle mode with a small letter at the top of the display, D, R, or G usually.

The left side of the equation produces just x.

\sin{x}=.945\\\\\sin^{-1}(\sin{x})=\sin^{-1}(.945)\\x=\sin^{-1}(.945) \approx 70.9^\circ

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Solve:-

2.39 = decimal

2.39 × 100 = 239
239%

2.39 = C. 239%
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So, therefore 5/7 is longer.
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A student was asked to rewrite using only the associative property of multiplication. Which is the correct response?
tatiyna

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1 year ago
Data were collected on random specimens of Yellowfin tuna from 1991 and 2010. For the sample of 231 specimens of Yellowfin tuna,
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Answer:

95% confidence interval: (0.325 ,0.383)

Step-by-step explanation:

We are given the following in the question:

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95% confidence interval:

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6 0
3 years ago
Please help me solve this answer it all for me please
mestny [16]

Answer:

The slopes are

m1=\dfrac{2}{5}, m2=-\dfrac{5}{2}

Therefore, the equations are equations of <u>  Perpendicular Lines .</u>

Step-by-step explanation:

Given:

y=\dfrac{2}{5}\times x + 1    ......................Equation ( 1 )

5x+2y=-4\\\\\therefore y = \dfrac{-5}{2}\times x-2   ..............Equation ( 2 )

To Find:

Slope of equation 1 = ?

Slope of equation 2 = ?

Solution:

On comparing with slope point form

y=mx+c

Where,

m = Slope

c = y-intercept

We get

Step 1.

Slope of equation 1 = m1 = \dfrac{2}{5}

Step 2.

Slope of equation 1 = m2 = -\dfrac{5}{2}

Step 3.

Product of Slopes = m1 × m2 = \dfrac{2}{5}\times -\dfrac{5}{2}=-1

Product of Slopes = m1 × m2 = -1

Which is the condition for Perpendicular Lines

The slopes are

m1=\dfrac{2}{5},m2=-\dfrac{5}{2}

Therefore, the equations are equations of <u>  Perpendicular Lines . </u>

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