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Sveta_85 [38]
3 years ago
10

Help me please asap​

Mathematics
2 answers:
Simora [160]3 years ago
8 0
5/6!!

Hope you get it right
Juliette [100K]3 years ago
4 0

Answer:

5/6

Step-by-step explanation:

2/

3

: 4/

5

= 2/

3

· 5/

4

= 2 · 5/

3 · 4

= 10/

12

= 2 · 5/

2 · 6

= 5/

6

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After doing some work in the house, Bob and Carol want to put a concrete patio on the side of the house to keep people from trac
alisha [4.7K]

Answer:

V=3.098 yd³

Step-by-step explanation:

To answer this question we need to work with formula of the Volume of rectangular prism, the patio. Once it is required 1 inch deep. Some relations will be useful.

As 1 yard = 1 feet/3

1 yard = 1 inch/36

1 feet=12 inches

a) 23 feet 9 inches

23 ft 9''=23 +9/12=23.75 ft

b)10 feet  1 inch

10 feet  1" = 10ft + 1/12=10.083 ft

c)4 inches: 4/12 =0.33

V= w.l.h

V=23.75*10.083*0.33=79.025 ft³

Converting from cubic yard to cubic feet:

V≈79.025 : 27 yd³=2.926 yd³

Considering the possible spillage due to uneven base. ( adding 5%of V)

V≈ 2.92+0.05*(2.92)=3.098 yd³

7 0
3 years ago
Read 2 more answers
PLZZZZZZZ HELPPP !!!!!!!!!!
Over [174]
1. 142 degrees
2. 45 degrees
6 0
3 years ago
Read 2 more answers
Suppose the students who scored 85 and 90 on the math test again
olga55 [171]
That means that they did the same as last time they took the test
8 0
3 years ago
According to a survey of 100 people regarding their movie attendance in the last year, 40 had seen a science fiction movie, 55 h
erastovalidia [21]

Answer:

The probability that at least one movie had seen P(S∪(AD)∪H) = 0.75

Step-by-step explanation:

The total number of movie attendance in the last year n =100

Let 'S' be the event had seen science fiction movie

The probability of that the event had seen science fiction movie

P(S) = 40/100 = 0.4

Let 'AD' be the event had seen adventure  movie

the probability of that  the event had seen adventure  movie

P(AD) =55/100 = 0.55

Let 'H' be the event had seen Horror movie

The probability of that the event had seen Horror movie

P(H) =20/100 = 0.2

given data 25 had seen a science fiction movie and an adventure movie

The probability of that the seen a science fiction movie and an adventure movie

that is P(S∩(AD)) = 25/100=0.25

Given  5 had seen an adventure movie and a horror movie

The probability of that the seen adventure movie and a horror movie

That is P((AD)∩ H) = 5/100=0.05

Given  5 had seen an science movie and a horror movie

The probability of that the seen science movie and a horror movie

That is P((S∩ H) = 15/100=0.15

Given only 5 people had seen a movie from all three categories.

The probability of that the seen a movie from all three categories.

That is P(S∩(AD)∩H) =5/100=0.05

The probability that at least one movie had seen P(S∪(AD)∪H) =

              =  P(S)+P(AD)+P(H) - P(S∩(AD)-P((AD)∩ H)-P((S∩ H) + P(S∩(AD)∩H)

              = 0.4+0.55+0.2-0.25-0.05-0.15+0.05

              = 0.75

3 0
4 years ago
Find the simplified product.
konstantin123 [22]

Answer:

first multiply 2x with 8

\frac{16x}{ {x}^{2}  + 6x}

you see in down there is x common so take it as common

\frac{16x}{x(x + 6)}

now we have x on top as well as in bottom cut them

\frac{16}{x + 6}

here is answer

7 0
3 years ago
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