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Volgvan
3 years ago
11

Help with diagram please

Mathematics
2 answers:
Alchen [17]3 years ago
5 0
29 because of those circles that overlap, just count the numbers in the run circle that do not overlap with walk in any way.
Kazeer [188]3 years ago
3 0
29.
You have 11 for those who only ran and 18 for those who ran and stretched.
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Use the distributive property to write an equivalent expression.<br> 2(8v+2)
andreyandreev [35.5K]

Answer:

16v+4

Step-by-step explanation:

2(8v+2) = 16v+4

4 0
2 years ago
Find the derivative of
kirill [66]

Answer:

\displaystyle y'(1, \frac{3}{2}) = -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Functions
  • Function Notation
  • Terms/Coefficients
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle y = \frac{3}{2x^2}<u />

\displaystyle \text{Point} \ (1, \frac{3}{2})

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Rewrite]:                                            \displaystyle y = \frac{3}{2}x^{-2}
  2. Basic Power Rule:                                                                                             \displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}
  3. Simplify:                                                                                                             \displaystyle y' = -3x^{-3}
  4. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle y' = \frac{-3}{x^3}

<u>Step 3: Solve</u>

  1. Substitute in coordinate [Derivative]:                                                              \displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}
  2. Evaluate exponents:                                                                                         \displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}
  3. Divide:                                                                                                               \displaystyle y'(1, \frac{3}{2}) = -3

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0
3 years ago
Please help with solving this problem....!!!
kifflom [539]

Answer:

The Average Temperature for the week is -1°C

Step-by-step explanation:

First to find the average, you have to combine all the numbers

-3-4+0-2+0+3-1 = -7

Then you have to divide the total, with the number of numbers used to combine to make the total

-7 ÷ 7 = -1

The average temperature is -1°C

6 0
3 years ago
Please help ASAP!!!!!!!!!!
zepelin [54]

Answer:

(c-a, 0)

Step-by-step explanation:

The horizontal space between (c, b) and P is the same as the space between (a, b) and O.

Coordinates are written (x, y), where x is for horizontal space.

P is on the x-axis, making the y-coordinate 0.

(a+c, 0) would be to the right of the entire parallelogram.

(c, 0) would be directly below (c, b).

(a-c, 0) would be to the left of the entire parallelogram and in the other quadrant.

4 0
3 years ago
A survey showed that 77​% of adults need correction​ (eyeglasses, contacts,​ surgery, etc.) for their eyesight. If 22 adults are
Sveta_85 [38]

Answer:

The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight​ correction .

Step-by-step explanation:

A survey showed that 77​% of adults need correction for their eyesight.

If 22 adults are randomly​ selected, find the probability that no more than more than 11 of them need correction for their eyesight.

n =22

p = 0.77

q = 1-p = 1- 0.77=0.23

We are supposed to find P(x\leq 11)

P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)

Formula : P(x=r)=^nC_r p^r q^{n-r}

P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}

Using calculator

P(x\leq 11)=0.00512

So, The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight​ correction .

3 0
3 years ago
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