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3 years ago

Solve the following system of equations graphically.

Mathematics

2 answers:

Flauer [41]3 years ago

7 0

Answer:

{(2, 1)}

Step-by-step explanation:

The graph shows the only solution to be the point (2, 1). Hence the solution set will be a set containing one element—that point:

{(2, 1)}

Korolek [52]3 years ago

5 0

Answer:

The solution set is:

{(2,1)}

Step-by-step explanation:

We plot the graphs of the equations:

y = 2x - 3

x + y = 3

The point of intersection of the two curves will be the solution of the above equations.

As we can see from the graph the solution set is:

{(2,1)}

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mezya [45]

line QP =

11.5*(11.5 +24) = 11.5 * 35.5 = 408.25

SqRT(408.25) = 20.205

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3 years ago

Read 2 more answers

Is this the correct answer?

Shtirlitz [24]

Answer:

yes

Step-by-step explanation:

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3 years ago

Part 1: Given triangle ABC and AC = BC, find a and the side lengths of the triangle. C 6a - 8 4a-2 MathBits.com A B Side BC = Si

hoa [83]

Answer: a = 2; AC = BC = 10

Step-by-step explanation:

AC = BC => 6a - 8 = 4a - 2

<=> 2a = 6

<=> a = 3

=> AC = 6.3 - 8 = 10

AC = BC => BC = 10

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3 years ago

Hannah purchased three items at the store for $7.05, $8.12, and $3.97. She paid for

vichka [17]

Answer:

She should receive $30.86

Step-by-step explanation:

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6 0

3 years ago

The number of internet users in mexico between 2004 and 2008 can be modeled as u(t) = 8.02(1.17t) million users where t is the n

maxonik [38]

Answer:

a) 1.479 Million

b) 36.9%

c) 13.668%

Step-by-step explanation:

The complete question is attached in the image below.

The number of internet users in Mexico between 2004 and 2008 is modelled by the following equation:

$u(t)=8.02(1.17)^{t}$

Where, u(t) is in millions and t is the number of years since 2004.

Part a) Rate of change of internet users between 2004 and 2006

The rate of change of a function is defined as:

$\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}$

We have to find the rate of change between 2004 and 2006. For 2004 t = 0, and for 2006, t = 2. So the rate of change for the given function will be:

$\frac{u(2)-u(0)}{2-0}\\\\ =\frac{8.02(1.17)^{2}-8.02(1.17)^{0}}{2}\\\\ =1.479$

Thus, the average rate of change in number of internet users in Mexico from between 2004 and 2006 was 1.479 million.

Part b) Percentage change of internet users between 2004 and 2006

The formula to calculate the percentage change is:

$\frac{\text{New value - Original Value}}{\text{Original Value}} \times 100\%$

Here, New value means the users in 2006 and original value means the users in 2004.

Using the values in this formula, we get:

$\frac{8.02(1.17)^{2}-8.02(1.17)^0}{8.02(1.17)^{0}} \times 100\%\\\\ =36.89\%$

Thus, the percentage change in the number of internet users between 2004 and 2006 was 36.89%

Part c) Percentage of internet users in 2008

For 2008, t would be equal to 4.

So, the number of internet users in Mexico in 2008 would be = $8.02(1.17)^{4}=15.02857542$ million = 15,028,575 (rounded to nearest integer)

Total population of Mexico in 2008 = 109,955,400

We have to calculate what percentage of Mexico population was Internet users in 2008. The formula for this would be:

$\frac{\text{Concerned Value}}{\text{Total Value}} \times 100\%$

Here, concerned value is the number of internet users and total value is the total population. Using the values in this formula we get:

$\frac{15028575}{109955400} \times 100\%\\\\=13.668\%$

Thus, 13.668% of the population was internet users in 2008 in Mexico.

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3 years ago