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kodGreya [7K]
2 years ago
15

How can you quickly expand a binomial raised to a power?

Mathematics
1 answer:
bixtya [17]2 years ago
8 0

Answer:

Step-by-step explanation:

dssssssssss

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Eight less than seven times a number is the same as four more than three times a number​
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minus it

Step-by-step explanation:

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Who tryin to talk thats not in there feelins
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Graph the image of the given triangle under a dilation with a scale factor of −2 and center of dilation (0, 0) .
Ronch [10]

To dilate an object means to enlarge or reduce the size of the object. The scale factor will determine how much larger or smaller the object will become.  If this factor is greater than 1, the object will increase in size. Otherwise, if the factor is less than 1, the object will decrease in size. So, the dilated object will be similar to its original. On the other hand, when corresponding points of the original and dilated figures are connected by straight lines, the center of dilation is the point where all the lines meet. In this problem, the center is (0, 0). When the center is the origin we need to multiply all the original coordinates of the object by the scale factor given. So:


A(-4, 1) \rightarrow A'=-2(-4,1) \rightarrow A'(8,-2) \\ \\ B(-3, -4) \rightarrow B'=-2(-3,-4) \rightarrow B'(6,8) \\ \\ C(-2, -2) \rightarrow C'=-2(-2,-2) \rightarrow C'(4,4)


So, the graph of the dilated triangle is shown in the Figure below

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3 years ago
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G(t)=t³+5t²; Find g(-1)​
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I need points sorry bbh

Step-by-step explanation:

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6 0
3 years ago
I need help please ASAP thank you
kirza4 [7]

Answer:

The products of AB and BA is given by

AB=\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]

BA=\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]

Step-by-step explanation:

Given the matrices A=\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right] and

B=\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]

To find the product AB and BA

AB=\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right] \left[\begin{array}{cc}1 & -1\\-3 &0\end{array}\right]

=\left[\begin{array}{cc}6+15& -6+0\\-3+12&3-0\end{array}\right]

Therefore the product of AB is

AB=\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]

BA=\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right] \left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]

=\left[\begin{array}{cc}6+3& -5+4\\-18+0&15+0\end{array}\right]

Therefore the product of BA is

BA=\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]

The products of AB and BA is given by

AB=\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]

BA=\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]

6 0
3 years ago
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