Answer:
minus it
Step-by-step explanation:
Answer:
me :/
Step-by-step explanation:
To dilate an object means to enlarge or reduce the size of the object. The scale factor will determine how much larger or smaller the object will become. If this factor is greater than 1, the object will increase in size. Otherwise, if the factor is less than 1, the object will decrease in size. So, the dilated object will be similar to its original. On the other hand, when corresponding points of the original and dilated figures are connected by straight lines, the center of dilation is the point where all the lines meet. In this problem, the center is (0, 0). When the center is the origin we need to multiply all the original coordinates of the object by the scale factor given. So:

So, the graph of the dilated triangle is shown in the Figure below
Answer:
I need points sorry bbh
Step-by-step explanation:
hh
Answer:
The products of AB and BA is given by
AB=![\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D21%26-6%5C%5C%209%263%5Cend%7Barray%7D%5Cright%5D)
BA=![\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%26-1%5C%5C-18%2615%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given the matrices A=
and
B=![\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-1%5C%5C-3%260%5Cend%7Barray%7D%5Cright%5D)
To find the product AB and BA
AB=![\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right] \left[\begin{array}{cc}1 & -1\\-3 &0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%26-5%5C%5C-3%26-4%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%20%26%20-1%5C%5C-3%20%260%5Cend%7Barray%7D%5Cright%5D)
![=\left[\begin{array}{cc}6+15& -6+0\\-3+12&3-0\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%2B15%26%20-6%2B0%5C%5C-3%2B12%263-0%5Cend%7Barray%7D%5Cright%5D)
Therefore the product of AB is
AB=![\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D21%26-6%5C%5C%209%263%5Cend%7Barray%7D%5Cright%5D)
BA=
![\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%26-5%5C%5C-3%26-4%5Cend%7Barray%7D%5Cright%5D)
![=\left[\begin{array}{cc}6+3& -5+4\\-18+0&15+0\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%2B3%26%20-5%2B4%5C%5C-18%2B0%2615%2B0%5Cend%7Barray%7D%5Cright%5D)
Therefore the product of BA is
BA=![\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%26-1%5C%5C-18%2615%5Cend%7Barray%7D%5Cright%5D)
The products of AB and BA is given by
AB=![\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D21%26-6%5C%5C%209%263%5Cend%7Barray%7D%5Cright%5D)
BA=![\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%26-1%5C%5C-18%2615%5Cend%7Barray%7D%5Cright%5D)