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mojhsa [17]
2 years ago
14

Solve the inequality. Graph and check your solutions.

Mathematics
1 answer:
Elza [17]2 years ago
4 0

Answer:

I am sorry just today we start this lesson

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Fill in the missing blinks
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Find the values of x and y. Pls helpI’m helpless at math
Svetradugi [14.3K]

Answer:

  • x = 1
  • y=\frac{\sqrt{3}}{2}  

Step-by-step explanation:

From the given right-angle triangle

The angle = ∠60°

  • The adjacent to the angle ∠60° is 1/2.
  • The opposite to the angle ∠60° is y.

The hypotenuse = x

<u>Determining the value of x:</u>

Using the trigonometric ratio

cos 60° = adjacent / hypotenuse

substituting adjacent = 1/2 and hypotenuse = x

cos\:60^{\circ }=\:\:\frac{\frac{1}{2}}{x}

\cos \left(60^{\circ \:}\right)=\frac{1}{2x}

\frac{1}{2}=\frac{1}{2x}          ∵ cos (60°) = 1/2

2x=2

Dividing both sides by 2

\frac{2x}{2}=\frac{2}{2}

Simplify

x=1

Thus, the value of hypotenuse x is:

x = 1

<u>Determining the value of y:</u>

Using the trigonometric ratio

sin 60° = opposite / hypotenuse

As we have already determined the value of hypotenuse x = 1

substituting opposite = y and hypotenuse = 1

sin 60° = y/1

y = 1 × sin 60°

y=\frac{\sqrt{3}}{2}       ∵  \sin \left(60^{\circ \:}\right)=\frac{\sqrt{3}}{2}

Therefore, the value of y is:

y=\frac{\sqrt{3}}{2}      

Summary:

  • x = 1
  • y=\frac{\sqrt{3}}{2}    
5 0
3 years ago
Which statements about the graph of the function f(x) = –x2 – 4x + 2 are true? Check all that apply.
Ipatiy [6.2K]
Statements 2, 3, and 5 are true based on the graph of this function.

4 0
3 years ago
Read 2 more answers
Spherical ball of lead has a diameter of 5.5 cm . what is the mass of the sphere if lead has a density of 11.34 g/cm3? (the volu
umka21 [38]
To know the mass of the sphere given the density , we first define density as

D = Mass / volume

now we have a value of density but doesn't have volume so we compute for it using the given radius 5.5 cm

V = <span>(4/3)πr^3 

so 
mass  =  D (volume)
mass = 11.34 (</span>(4/3)π(5.5)^3 )

mass = 7902.96 g 

<span>Hope my answer would be a great help for you.    
If </span>you have more questions feel free to ask here at Brainly.

<span> </span>

4 0
3 years ago
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