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mojhsa [17]
2 years ago
14

Solve the inequality. Graph and check your solutions.

Mathematics
1 answer:
Elza [17]2 years ago
4 0

Answer:

I am sorry just today we start this lesson

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What is f(–3) for f(x) = 2x2 – x + 5?<br> A) 11 <br> B) 17 <br> C) 20 <br> D) 26
nirvana33 [79]

Answer: D

<u>Step-by-step explanation:</u>

f(x) = 2x² - x + 5

f(-3) = 2(-3)² - (-3) + 5

      = 2(9) + 3 + 5

      = 18 + 3 + 5

      = 26

6 0
3 years ago
Polygons ABCD and EFGH are similar. What is the perimeter of EFGH?
Rom4ik [11]
If polygons ABCD and EFGH are similar, then their perimeters most likely are also similar. Polygon EFGH also have the same perimeter with polygon ABCD. Having similar polygons is referred as congruent polygons. <span>Two figures are said to be congruent when they have the same shape and size or if one object is a mirror image of the other object.<span> </span></span>
5 0
3 years ago
The sum of the ages of Berma, her mother Rinna and her father Erwin is 80. Two years from now, Rinna’s age will be 13 less than
jekas [21]

Answer: Berma is 5 years old

Rinna is 38 years old

Erwin is 37 years old

Step-by-step explanation:

Let x represent Berma's age

Let y represent Rinna's age

Let z represent Erwin's age

Since the sum of their ages is 80,

x + y + z = 80 - - - - - - -1

Two years from now, Rinna’s age will be 13 less than the sum of Erwin’s age and twice Berma’s age. This means that

y +2 = [ (z+2) + 2(x+2) ] - 13

y +2 = z + 2 + 2x + 4 - 13

2x - y + z = 13 + 2 - 4 -2

2x - y + z = 9 - - - - - - -2

Three years ago, 15 times Berma’s age was 5 less than the age of Rinna. It means that

15(x - 3) = (y - 3) - 5

15x - 45 = y - 3 - 5

15x - y = - 8 + 45

15x - y = 37 - - - - - - - -3

From equation 3, y = 15x - 37

Substituting y = 15x - 37 into equation 1 and equation 2, it becomes

x + 15x - 37 + z = 80

16x + z = 80 + 37 = 117 - - - - - - 4

2x - 15x + 37 + z = 9

-13x + 2 = -28 - - - - - - - - -5

subtracting equation 5 from equation 4,

29x = 145

x = 145/29 = 5

y = 15x - 37

y = 15×5 -37

y = 38

Substituting x= 5 and y = 38 into equation 1, it becomes

5 + 38 + z = 80

z = 80 - 43

z = 37

6 0
3 years ago
Pls help me solve this pls show how you got the answer
Rudiy27

Answer:

my answer is in this picture.

5 0
3 years ago
The formula to find the period of orbit of a satellite around a planet is T2=(4π2GM)r^3 where r is the orbit’s mean radius, M is
andriy [413]
<span>The formula to find the period of orbit of a satellite around a planet is T^2=(4π^2/GM)r^3 where r is the orbit’s mean radius, M is the mass of the planet, and G is the universal gravitational constant. To find the value of r, we rewrite r^3 = (T^2GM/4π^2) or r = (T^2GM/4π^2)^(1/3)</span>
5 0
3 years ago
Read 2 more answers
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