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mojhsa [17]
2 years ago
14

Solve the inequality. Graph and check your solutions.

Mathematics
1 answer:
Elza [17]2 years ago
4 0

Answer:

I am sorry just today we start this lesson

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D. Evaluate each of the following. (5 points)
Harrizon [31]

Problem 1

f(x) = x + 1/x

f(1) = 1 + 1/1

f(1) = 1 + 1

f(1) = 2

Answer: 2

============================================

Problem 2

(f o f)(1) = f( f(1) )

(f o f)(1) = f( 2 )

(f o f)(1) = 2 + 1/2

(f o f)(1) = 4/2 + 1/2

(f o f)(1) = 5/2

Answer:  5/2

============================================

Problem 3

(f o f o f)(1) = f(  f(f(1)) )

(f o f o f)(1) = f(  (f o f)(1) )

(f o f o f)(1) = f(  5/2 )

(f o f o f)(1) = 5/2 + 1/(5/2)

(f o f o f)(1) = 5/2 + 2/5

(f o f o f)(1) = 25/10 + 4/10

(f o f o f)(1) = 29/10

Answer: 29/10

============================================

Problem 4

(f o f o f o f)(1) = f(   f(f(f(1))   )

(f o f o f o f)(1) = f(   (f o f o f)(1)    )

(f o f o f o f)(1) = f(   29/10   )

(f o f o f o f)(1) = 29/10 + 1/(29/10)

(f o f o f o f)(1) = 29/10 + 10/29

(f o f o f o f)(1) = 841/290 + 100/290

(f o f o f o f)(1) = 941/290

Answer: 941/290

============================================

Problem 5

(f o f o f o f o f)(1) = f(   f(f(f(f(1))))   )

(f o f o f o f o f)(1) = f(   (f o f o f o f)(1)  )

(f o f o f o f o f)(1) = f(   941/290  )

(f o f o f o f o f)(1) = 941/290 + 1/(941/290)

(f o f o f o f o f)(1) = 941/290 + 290/941

(f o f o f o f o f)(1) = 885481/272890 + 84100/272890

(f o f o f o f o f)(1) = 969581/272890

Answer: 969581/272890

4 0
3 years ago
Read 2 more answers
A figure has side lengths as marked in the diagram. <br> What is the area of the figure?
vovangra [49]

Answer:

132.4

Step-by-step explanation:

7 0
3 years ago
How to solve this problem?<br> -3 d +7 &gt; 25
sp2606 [1]
Answer to your question:

D = d < -6
8 0
3 years ago
Read 2 more answers
Please help me as soon as posable!! In hurry!!(24 points)
attashe74 [19]

The sequence is geometric, so

a_n = r a_{n-1}

for some constant r. From this rule, it follows that

a_3 = r a_2 \implies 20 = 2r \implies r = 10

and we can determine the first term to be

a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15

Now, by substitution we have

a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots

and so on down to (D)

a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15

(notice how the exponent on r and the subscript on a add up to n)

4 0
2 years ago
The density of a certain material is such that it weighs 4 kilograms per cup of volume. Express this density in pounds per liter
777dan777 [17]

Answer: The answer is 8.8 pounds per litre. I just helped you, what’s your name and how are you? Mines is very good. :)

Step-by-step explanation:

6 0
3 years ago
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