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USPshnik [31]
2 years ago
12

Help I’ll give a lot of points

Mathematics
2 answers:
professor190 [17]2 years ago
5 0

Answer:

The answer is H or J either those two and I'm sure of it.

Step-by-step explanation:

;)

Nastasia [14]2 years ago
3 0
G is correct explanation below \/

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Please help this test is a big part of my grade!<br> (will give brainliest)
djyliett [7]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
Tarana mailed 20 greetings cards. 9 of them were mailed to USA. What percentage of the cards were mailed to USA?
Elza [17]

Answer:

45%

Step-by-step explanation:

9/20=0.45 (Divide it first), 45/100=45% (45/100 because 100 makes 1 whole -all 20 cards-)

7 0
3 years ago
I NEED HELP WITH THIS!
Ymorist [56]
9 is the answer for that problem
5 0
3 years ago
Read 2 more answers
I NEED HELP ASAP!!!!!
viva [34]

Answer:

1 is 12

2 is 1/2 and 3/4

3 is 802,083

4 is 96

5 is 23

6 is 2/3

3 0
3 years ago
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