Let's assume there's a fourth place too, and fourth place is the one where it's no prize.
4 3 2 1 (4 3 X X)
4 3 1 2 (^ but 3rd and 4th digit exchanged)
4 2 3 1 (4 2 X X)
4 2 1 3 etc.,.
4 1 2 3
4 1 3 2
As you can see, there are six possibilities assuming first swimmer was fourth.
Now, there would be six possibilities if the first swimmer was third, and same goes for second and first.
Thus, 6 x 4 = 24, there are 24 possibilities to award the 3 prizes (plus 1 no-prize)
Simple Mathematical Way:
4 x 3 x 2 x 1 = 4! = 24
There are 24 ways.
Answer
A. 42 tickets
Explanation
Since everyone must go on the ride together the number of tickets must be a multiple of 8 (since there are 8 people). 42 is the only number that is not a multiple of 8.
Answer:
If the first day is January 1st, 2017 on a "sunday"(Not saturday), that means that the last day is December 31, 2017 on a sunday. (Pog moment for mee)
Step-by-step explanation:
Answer:
I think you would have to do 2 times 7
Answer:
Step-by-step explanation:The solution to the system of equations are;
x = -4/3
y = 5/3
Step-by-step explanation:
To find the Solution, we would carry the Operation simultaneously.
4x + 2 = -2y .........(i)
6y - 18 = 6x ..........(ii)
First let's rearrange the equations, to make the journey smoother
2y + 4x = -2 ...........(iii)
6y - 6x = 18 ...........(iv)
Let's Multiply equation (III) by 3 so as to have a uniform spot to begin elimination.
3.2y + 3.4x = -2 . 3
6y + 12x = -6............... (v)
Let's subtract equation (v) from equation (iv)
= 0y - 18x = 24
-18x = 24
x = - 24 / 18
x = -4/3
Let's substitute (x = -4/3) in equation (ii), so that we can solve for the value of y:
6y - 18 = 6x
6y - 18 = 6 (-4/3)
6y - 18 = -8
6y = -8 + 18
6y = 10.
y = 10 / 6
y = 5/3
The solution to the system of equations are;
x = -4/3
y = 5/3
