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DaniilM [7]
3 years ago
11

4 plates and 3 cups cost 20.90 dollars. 5 plates and 4 cups cost 26.50 dollars. Each plate costs the same amount as the other pl

ates, and each cup costs the same amount as the other cups. What is the cost of 1 plate? What is the cost of 1 cup?
Mathematics
1 answer:
shutvik [7]3 years ago
3 0

Answer:

Hope this helps you understand...

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Find the percent of increase from 4.5 inches to 13.5 inches.
jolli1 [7]

Answer:

200%

Step-by-step explanation:

Increase: 13.5 - 4.5 = 9

%increase:

Increase/initial × 100

9/4.5 × 100

200%

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Fittoniya [83]

The conversion from yards to feet and feet to miles are given.

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253 is closer to 300. .46 is close to .5 or 1/2

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(1.25-0.4)/7+4x3
Natasha_Volkova [10]

Answer:

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Find the work done by the force field F(x,y,z)=6xi+6yj+6k on a particle that moves along the helix r(t)=3 cos(t)i+3sin(t)j+2 tk,
kramer

Answer:

the work done by the force field = 24 π

Step-by-step explanation:

From the information given:

r(t) = 3 cos (t)i + 3 sin (t) j + 2 tk

= xi + yj + zk

∴

x = 3 cos (t)

y =  3 sin (t)

z = 2t

dr = (-3 sin (t)i + 3 cos (t) j + 2 k ) dt

Also F(x,y,z) = 6xi + 6yj + 6k

∴  F(t) = 18 cos (t) i + 18 sin (t) j +6 k

Workdone = 0 to 2π ∫ F(t) dr

\mathbf{= \int \limits ^{2 \pi} _{0} (18 cos (t) i + 18 sin (t) j +6k)(-3 sin (t)i+3cos (t) j +2k)\ dt}

\mathbf{= \int \limits ^{2 \pi} _{0} (-54 \ cos (t).sin(t) + 54 \ sin (t).cos (t) + 12 )    \ dt}

\mathbf{= \int \limits ^{2 \pi} _{0} 12    \ dt}

\mathbf{= 12 \times 2 \pi}

= 24 π

3 0
4 years ago
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