Hello.
Have a beautiful and joyful day ahead.
You have a lot of questions here, try breaking them up into multiple posts and you may get more responses.
I will help with some.
<span>(x+3)=0
The solution is just -3.
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3m(m-4)=0
The two solutions are 0 and 4.
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(r-3)(r+2)=0
The two solutions are and 3 and -2.
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I hope this gets you started in the right direction.
According to me the probability is 1/4, because there are 4 possible outcomes when two coins are flipped - TT, TH, HT, HH.
<span>Also, would it matter if the coins are flipped one after other rather than together</span>
C=2πr r radius it would be right
