Answer:y=5x
Step-by-step explanation:
B
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an
S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d] → Equation (1)
S=an+an−1+an−2+an−3+...+a1
S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d] → Equation (2)
Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)
2S=n(a1+an)
S=n/2(a1+an)
Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
Answer:
E
Step-by-step explanation:
Its simple
Explanation:
As his uniform is made up of tan or blue pants and a blue or white collared shirt.
So, there are possibly four combinations which are as follows:
- tan pants/blue shirt
- tan pants/white shirt
- blue pants/blue shirt
- blue pants/white shirt
As Benjamin carries an extra piece of white shirt. So, he has a little bit better than 25% chance of wearing his favorite combination.
So,
- Probability of getting tan pants = 2/4 = 1/2
- Probability of getting white shirt = 3/5
The probability of getting both can be computed by simply multiplying 2/4 and 3/5.
So,
- Probability of getting both = 1/2 × 3/5 = 3/10 ⇒ 30%
<em>Keywords: probability, chance</em>
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