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Lady_Fox [76]
3 years ago
11

Use two 2-Column proofs to show that either diagonal of a rectangle will create two congruent triangles?

Mathematics
1 answer:
tangare [24]3 years ago
6 0
<span>Given: Rectangle ABCD 
Prove: ∆ABD≅∆CBD 
Solution:
                      
           <span> Statement                                       Reason 
</span>
  ABCD is a parallelogram          Rectangles are parallelograms since the                                                          definition of a parallelogram is a quadrilateral                                                    with two pairs of parallel sides.

Segment AD = Segment BC       The opposite sides of a parallelogram are     Segment AB = Segment CD       congruent. This is a theorem about the                                                              parallelograms.

</span>∆ABD≅∆CBD                             SSS postulate: three sides of ΔABD is                                                           equal to the three sides of ∆CBD<span>


</span><span>Given: Rectangle ABCD 
Prove: ∆ABC≅∆ADC
</span>Solution:
                      
           <span> Statement                                       Reason 
</span>
    Angle A and Angle C                 Definition of a rectangle: A quadrilateral     
        are right angles                      with four right angles.

        Angle A = Angle C                 Since both are right angles, they are                                                                  congruent

Segment AB = Segment DC       The opposite sides of a parallelogram are     Segment AD = Segment BC       congruent. This is a theorem about the                                                              parallelograms.

            ∆ABC≅∆ADC                   SAS postulate: two sides and included                                                         angle of ΔABC is congruent to the two                                                         sides and included angle of ∆CBD
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Find C to form completing Square<br> <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B5x%20%2B%20C" id="TexFormula1" title="x^
postnew [5]

Answer:

\frac{25}{4}  (or 6.25)

Step-by-step explanation:

Let's do a simple square problem to see the relationship between the elements of the resulting equation...

(x+3)(x+3) = x(x+3) + 3(x+3) = x^{2} +3x + 3x + 9 = x^{2} + 6x + 9

As you see, the number of 'x' (6) is the double of the numeric part of the binomial expression (3), while the numeric-only part (9) is the square of the numeric part of the binomial expression (3).

So, if we look at the formula from the problem, we see the the number of 'x' is 5. To obtain the C value, we need to divide the 5 by 2... then get the square value of the result.

\frac{5}{2} * \frac{5}{2} = \frac{25}{4}  (or 6.25)

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Gre4nikov [31]
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Step-by-step explanation:

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0.27055*1,000=

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