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Vesnalui [34]
2 years ago
7

Can someone help with this please?

Mathematics
1 answer:
lbvjy [14]2 years ago
8 0

Answer:

900

Step-by-step explanation:

Might wanna double check. I rushed

(7m-2m^2n)^2

-42+144

900

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15 a2 - 6ab- 8 a2+ 20 - 5ab - 31 + a2- ab
Ivanshal [37]

Step-by-step explanation:

Remove the parentheses: 15a²-6ab+8a²+20+5ab-31+a²-ab Combine like terms: 24a²-2ab-11

Answer: 24a²-2ab-11

4 0
3 years ago
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Usain Bolt ran the 2012 Olympic 100-meter race in 9.63 seconds. If he runs at this rate on a road with a speed limit of 25 miles
djverab [1.8K]

Answer:

3874.5342

Step-by-step explanation:

9.63 divide by 100 = 0.0963

0.0963x40 234= 3874.5342

6 0
3 years ago
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​Joe's annual income has been increasing each year by the same dollar amount. The first year his income was ​$17 comma 90017,900
Vedmedyk [2.9K]

Answer:

In 17th year, his income was $30,700.

Step-by-step explanation:

It is given that the income has been increasing each year by the same dollar amount. It means it is linear function.

Income in first year = $17,900

Income in 4th year = $20,300

Let y be the income at x year.

It means the line passes through the point (1,17900) and (4,20300).

If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y-17900=\frac{20300-17900}{4-1}(x-1)

y-17900=\frac{2400}{3}(x-1)

y-17900=800(x-1)

y-17900=800x-800

Add 17900 on both sides.

y=800x-800+17900

y=800x+17100

The income equation is y=800x+17100.

Substitute y=30,700 in the above equation.

30700=800x+17100

Subtract 17100 from both sides.

30700-17100=800x

13600=800x

Divide both sides by 800.

\frac{13600}{800}=x

17=x

Therefore, in 17th year his income was $30,700.

5 0
3 years ago
Which of the graphs below would result if you made the leading term of the
Anettt [7]

Answer:

A%7.2= ( 7.5№) =(+--+) this is the best answer

3 0
3 years ago
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Can someone help me.​
salantis [7]

Answer:

see explanation

Step-by-step explanation:

substitute the values of x in the table into g(x)

Using the rule of exponents

a^{-m} = \frac{1}{a^{m} }

g(- 2) = 4^{-2} = \frac{1}{4^{2} } = \frac{1}{16}

g(- 1) = 4^{-1} = \frac{1}{4}

g(0) = 4^{0} = 1

g(1) = 4^{1} = 4

g(2) = 4² = 16

8 0
3 years ago
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