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lord [1]
3 years ago
9

A professional interior designer is purchasing wallpaper for two square walls. One wall is 4 feet wider than

Mathematics
1 answer:
gayaneshka [121]3 years ago
3 0

Let ones side be a and others be a+4

ATQ

\\ \sf\longmapsto a^2+(a+4)^2=170

\\ \sf\longmapsto a^2+a^2+8a+16=170

\\ \sf\longmapsto 2a^2+8a=154

\\ \sf\longmapsto a^2+4a=77

\\ \sf\longmapsto a^2+4a-77=0

\\ \sf\longmapsto a=7\:or\:a=-11

  • a can't be negative

\\ \sf\longmapsto a=7

  • a+4=7+4=11
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Silas just bought a used car for $5000. It loses value at a rate of 30% per year. The value of the car in n years is modeled by
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Answer:

$1200.50

plug 5 for n

5000(.7)^4

5000*.2401

=1200.5

8 0
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A middle school took all of its 6th grade students on a field trip to see a ballet at a theatre that has 2000 seats. The student
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4 years ago
120% of what number is 20.4
NeTakaya
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8 0
3 years ago
Help please i need this​
Arada [10]

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It is Answer B

Step-by-step explanation:

Hope this helped

7 0
3 years ago
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

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  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
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