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3 years ago

A line, y = mx +b, passes through the point (2,3) and is parallel to y = 2x + 3. What is the value of

Mathematics

1 answer:

diamong [38]3 years ago

4 0

Answer:

The value of b is 3

Step-by-step explanation:

mx is the slope and b is the y intercept. I hope this helps!

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If f(x) = x^2 - 2x and g(x) = 6x + 4, for what value of x does (f + g)(x) = 0?

larisa86 [58]

Answer:

x = -2

Step-by-step explanation:

$f(x) =x^2 -2x\:\: and \:\: g(x) = 6x + 4\\(f+g)(x) = f(x) + g(x) \\(f+g)(x) = x^2 -2x+ 6x + 4\\(f+g)(x) = x^2+4x + 4\\(f+g)(x) = (x+2)^2\\ 0 = (x+2)^2...[\because (f+g)(x) =0]\\0 = x+2\\\therefore x = -2$

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3 years ago

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Solve the following:<br> a. 4x^2 + 5x + 3 = 2x^2 − 3x<br> b. c^2 − 14 = 5c

Jet001 [13]

Answer:

(a) x = -0.418 , -3.581

(B) c = 6.855, -1.855

Step-by-step explanation:

(A) We have given equation $4x^2+5x+3=2x^2-3x$

$2x^2+8x+3=0$

On comparing with standard quadratic equation $ax^2+bx+c$

a = 2, b = 8 and c = 3

So roots of the equation will be $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-8\pm \sqrt{8^2-4\times 2\times 3}}{2\times 2}=\frac{-8\pm 6.324}{4}=-0.418,-3.581$

(b) $c^2-14=5c$

$c^2-5c-14=0$

a = 1, b = -5 and c= -14

So $c=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-(-5)\pm \sqrt{(-5)^2-4\times 1\times (-14)}}{2\times 1}=\frac{5\pm 8.71}{2}=6.855,-1.855$

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3 years ago

What is the rate of change?

Ulleksa [173]

sheesh these are easy its 4

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2 years ago

Find the new price for the markdown. Round to the nearest cent if necessary. $12.99 marked down 25%

Y_Kistochka [10]

$9.74

I like to do these equations backwards and multiply the first number by the opposite of it. ( think 1- the percent as a decimal) however, you can do this by converting the percent into a decimal and then subtracting that from the original number.

Have a great day!

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2 years ago

32 = 4(n – 5) and -s + 11 = 17 please solved Both of the following

valina [46]

Answer:

n=13 s=-6

Step-by-step explanation:

Hope this helps :)

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2 years ago

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