Answer:
(A) There should have been 5 outcomes of HT
(B) The experimental probability is greater than the theoretical probability of HT.
Step-by-step explanation:
Given
-- Sample Space
--- Sample Size
Solving (a); theoretical outcome of HT in 20 tosses
First, calculate the theoretical probability of HT
Multiply this by the number of tosses
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Solving (b); experimental probability of HT
Here, we make use of the table
---- Experimental Probability
In (a), the theoretical probability is:
---- Experimental Probability
By comparison;
Answer:
Imagine an easier version of this problem: You have a board 5 feet long that you must cut (divide, right?) into two equal parts. It is probably clear to you that you simply divide the length (5) by the number of parts you're dividing it into (2) to obtain the length of each piece (2.5 feet).
Use the same method for your problem 5 feet divided by 6 is 0.83 feet per piece.
We do not ordinarily divide feet into decimal portions, but instead into inches. Since an inch is 1/12 of a foot, you could simply say 5/6 = how many twelfths? or 5/6 = n/12 Solve this by inspection or by cross multiplying 5 times 12 equals n times 6. So n must equal 10, and your pieces of board are each 10 inches long.
Symmetric property of an Equality
The answer is not defined.
Explanation:
The given matrix is ![$\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%7B2%7D%20%26%20%7B4%7D%20%5C%5C%20%7B1%7D%20%26%20%7B-6%7D%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%7B1%7D%20%5C%5C%20%7B0%7D%5Cend%7Barray%7D%5Cright%5D%24)
The matrix ![$\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%7B2%7D%20%26%20%7B4%7D%20%5C%5C%20%7B1%7D%20%26%20%7B-6%7D%5Cend%7Barray%7D%5Cright%5D%24)
has dimensions 
This means that the matrix has 2 rows and 2 columns.
Also, the matrix ![$\left[\begin{array}{l}{1} \\ {0}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bl%7D%7B1%7D%20%5C%5C%20%7B0%7D%5Cend%7Barray%7D%5Cright%5D%24)
has dimensions 
This means that the matrix has 2 rows and 1 column.
Since, the matrices can be added only if they have the same dimensions.
In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.
Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.
Hence, the addition of these two matrices is not defined.
Your answer is -5.
This is because, if you expand the single bracket, you get -6x -3a, and since the other side of the equals sign is -6x + 15, then you need to do 15 ÷ -3 = -5.
I hope this helps!
