I wanna say B but i don’t remember i had that question before though
Answer:
ok
Step-by-step explanation:
Answer:
See solutions below
Step-by-step explanation:
For what values of X are the statements below true
A. 1x>x+1
x >x+1
x-x>1
0x > 1
x > 1/0
X >∞
B) |1-x|>3
The fucntion can both be positive and negative
For the negative function
-(1-x) > 3
-1+x > 3
x > 3+1
x > 4
For the positive function
1-x > 3
-x > 3 - 1
-x > 2
x < -2
Hence the required solutions are x > 4 and x < -2
c) For the equation
|x-15| < 0
-(x - 15) < 0
-x + 15 < 0
-x < -15
x > 15
Also x-15 < 0
x < 0+15
x < 15
Hence the required solution is x > 15 and x < 15
Answer:
Step-by-step explanation:
We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).
p = 12/100 = 0.12
number of success, x = 20
n = 200
the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)
From the binomial probability calculator,
P(x ≥ 20) = 0.84
Answer:
2n+3 < n-4
Step-by-step explanation:
Tooooooo easy XD
