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2 years ago

Juan wants to eat fewer than 800

Mathematics

1 answer:

brilliants [131]2 years ago

7 0

The two meals are green beans and cod dogs and pizza slice and carrots the total cost is 4.85$

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What is the final elevation if a butterfly starts at 20 m and changes -16 m

Fofino [41]

Answer:

Therefore the final elevation of the butterfly is 4 m.

Step-by-step explanation:

i) initial elevation = 20 m

ii) change in elevation = -16m

iii) therefore final elevation = initial elevation + change in elevation

= 20 m + (-16 m)

= (20 - 16) m

= 4 m

Therefore the final elevation of the butterfly is 4 m.

8 0

2 years ago

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Reika [66]

Answer:

The answer to the first question is 7.15

The answer to the second question is 1.73

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2 years ago

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Classify the following triangle. Check all that apply.

aksik [14]

B. acute and F. Scalene

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3 years ago

Write an equation in slope-intercept form of a line that has a slope of 1/2

andriy [413]

Answer: y=−12x+3.

Step-by-step explanation:

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2 years ago

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of <u>analytical geometry</u> is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$

$\mathsf{A} \triangle = \dfrac{12 + 14 - 18 - (-8 - 9 - 42)}{2}$

$\red{\mathsf{A} \triangle = \dfrac{67}{2} = 33,5u.a}$

Hope you enjoy it, see ya!)

$\green{\mathsf{FROM}}:$ Mozambique, Maputo – Matola City – T-3

DavidJunior17

3 0

3 years ago