The angle T1PT2 is 65-37=28 degree
use law of sine: sin37/PT2=sin28/7370, PT2=7370*sin37/sin28
Use a calcuator, I got the answer 9448
B. sin65=PA/PT2, PA=PT2*sin65=9448*sin65=8563
Step-by-step explanation:
The largest possible ellipse will have a semi-minor axis of 2 feet and a semi-major axis of 4 feet. If we center the board on the origin of the cartesian coordinate plane, we can derive the location of the foci and thus, the length of string he will need:
x^2 / 16 + y^2 / 4 = 1
Vertices:
(-4 , 0) , (4 , 0)
(0 , -2) , (0 , 2)
Answer: <ACB = 50 degrees
Step-by-step explanation: Since the interior angles of a triangle is always equal to 180 degrees, you would add both given degrees which is 40 and 90 (because of the right angle) and then subtract that answer (130) from 180
K=1
-2k + 10 + 2k = 5k + 5
10 = 5k + 5
5= 5k
K= 1
