Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Answer:
From top to bottom:
Simplify
Combine like terms
Subtract 3x from both sides
Add 14 on both sides
Step-by-step explanation:
Hope this helps
The lengths of sides of a triangle have to satisfy the triangle inequality, which states that the sum of the two shorter sides must exceed the length of the third side.
Here 9+8=17 (not greater), so these segments do not form a triangle.
X+y = 4, -----> y=4 - x
x² +(4-x)² =16
x² +16-2*4x+x² =16
2x² - 8x = 0
x(2x-8) = 0
2x-4=0, 2x=8, x=4
x=0 or x=4
If x=0, y=4-x=4-0=4.
If x=4, y= 4-x=4-4=0.
(0,4) or (4,0)
Check
x² +y² =16
For (0,4)
0²+4² =16
16 =16 True
For (4,0)
4² +0²=16
16=16 True
Answer (0, 4) and (4,0).
Complete question is;
Suppose we are testing the null hypothesis H0: μ = 20 and the alternative Ha: μ ≠ 20, for a normal population with σ = 5. A random sample of 25 observations are drawn from the population, and we find the sample mean of these observations is x¯ = 17.6. The P-value is closest to:
a. 0.0668.
b. 0.0082.
c. 0.0164.
d. 0.1336
Answer:
Option D
Step-by-step explanation:
We are given;
Null hypothesis; H0: μ = 20
Alternative hypothesis; Ha: μ ≠ 20
Population Standard deviation; σ = 5
Sample size; n = 25
Sample mean; x¯ = 17.6
Let's find the z-score from the formula;
z = (x¯ - μ)/(σ/√n)
z = (17.6 - 20)/(5/√5)
z = - 1.073
From online p-value from z-score calculator attached, using z = -1.073; two tailed hypothesis; significance value of 0.05,we have;
The P-Value is 0.283271.
Looking at the given options, the closest to the p-value is option D
