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3 years ago

A compound proposition that is always ___________ is called a contradiction. A. True B. False

Mathematics

1 answer:

alexandr1967 [171]3 years ago

3 0

Answer:

<em>A compound proposition that is always false is called a contradiction</em>

Step-by-step explanation:

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Estimate a 25% tip on a bill of $89.27 by first rounding the ball amount to the nearest ten dollars

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$22.32 or 22 dollars

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3 years ago

Need Help ASAP <br><br> How many weeks will it take to save $150 if I save $2.50 per week?

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Answer: 60 weeks.

Step-by-step explanation: 150 divided by 2.50 = 60

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2 years ago

Read 2 more answers

2) Ms. Van is going to build a small rectangular garden in a part of her yard. The

Zina [86]

Answer:

Area = 3x^2 + 4x

Step-by-step explanation:

Givens

W = x

L = 3x + 4

Formula

Area = L * W

Solution

Area = x(3x + 4)

Area = 3x^2 + 4x

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3 years ago

Cual es el valor de un esfero cuando la docena se compra en $7848? Area de un triangulo de 9 unidades de base y 6 unidades de al

aniked [119]

Answer:

a) $654

b) 27 unidades cuadradas

c) 721

Step-by-step explanation:

a) ¿Cuál es el valor de un bolígrafo cuando la docena se compra por $ 7848?

Una docena = 12

Por eso:

12 bolígrafos = $ 7848

1 bolígrafo = $ x

Cruz multiplicar

12 bolígrafos × $ x = 1 bolígrafo × $ 7848

$ x = 1 bolígrafo × $ 7848/12

$ x = $654

b) Área de un triángulo ¿9 unidades de base y 6 unidades de altura?

Área de un triángulo =

= 1/2 × Base × Altura

1/2 × 9 × 6

= 27 unidades cuadradas

c) Cien veces la suma de 4.5 con 2.71

Esto se calcula como:

100 × (4,5 + 2,71)

= 100 × (7.21)

= 721

6 0

2 years ago

Multiply.

Nady [450]

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Explanation:</h2>

Here we have the following expression:

$3\sqrt{22}\sqrt{58}\sqrt{18}$

So we need to simplify that radical expression. By property of radicals we know that:

$\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}$

So:

$3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}$

The prime factorization of 22968 is:

$22968=2^3\cdot 3^2\cdot11\cdot 29$

Hence:

$3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}$

By property:

$\sqrt[n]{a^n}=a$

So:

$3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}$

Finally:

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

3 0

3 years ago