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Delvig [45]
3 years ago
13

A compound proposition that is always ___________ is called a contradiction. A. True B. False

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

<em>A compound proposition that is always false is called a contradiction</em>

Step-by-step explanation:

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What part of an hour elapses from 3:12 P.M. to 4:30 P.M.?
sergejj [24]

Answer: \frac{13}{10} of an hour.


Step-by-step explanation:

1. You know that it is from 3:12 p.m. (48 minutes before 4:00 p.m.) to 4:30 p.m. (30 minutes after 4:00 p.m.)

2. Therefore, you must make the following addition:

48minutes+30minutes=78minutes

This is 78 minutes out of 1 hour (60 minutes).

3. Therefore, you have the following fraction:

\frac{78}{60}

4. Now, you must reduce the fraction:

\frac{78}{60}=\frac{13}{10}

5. The answer is 13/10 on an hour.

5 0
3 years ago
Can You Please Help Me ​
Illusion [34]

Answer:

A:   YES

B:   NO

C:   YES

Step-by-step explanation:

uhm, if you really need an explanation, here it goes

the opposite of an integer is its opposite value or if its a postitve integer the oposite woud be the negative integer, and thats all i got, hope this helps.

8 0
3 years ago
Read 2 more answers
Apply the Pythagorean Theorem to find the distance between points B and C.
Lyrx [107]

10 units

6^+8^=X^

36+64=x^

100=x^

10=x


3 0
4 years ago
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Calculate gcd(77, 30) by using the Euclidean algorithm. Find also integers u and v such that 49u + 30v = 1. Furthermore, find su
VladimirAG [237]

Answer:

1. gcd(77,30)=1

77=2*30+17\\30=1*17+13\\17=1*13+4\\13=3*4+1\\4=4*1+0

Since 1 is the last non zero remainder appearing in these equations then, 1 is the gcd of 77 and 30.

2. u=-11, v=18

Using the Euclidean Algorithm we have that

49=1*30+19\\30=1*19+11\\19=1*11+8\\11=1*8+3\\8=2*3+2\\3=1*2+1\\2=1*2+0

Now, we express the remainder as linear combinations of 49 and 30.

1&=3-2\\ &=3-(8-2*3)=3-8+2*3\\&=(11-8)-8+2(11-8)=3*11-4*8\\&=3*11-4(19-11)=7*11-4*19\\&=7(30-19)-4*19=7*30-11*19\\&=7*30-11(49-30)=\\&=18*30-11*49

Then 1=(-11)49+18*30

3. x=18

If 30x\equiv 1\text{mod 77} then

30x=k*77+1 for some k\in \mathbb{Z}.

Then, if k=7,

30x=7*77+1=540\\x=\frac{540}{30}=18

6 0
3 years ago
Solve the equation on the interval [0,2pi] 5sec(x)+7=-3
vovangra [49]

Answer:

Hello,

x\in \bigg\{\dfrac{2\pi}{3} ,\dfrac{4\pi}{3}\bigg\}\\

Step-by-step explanation:

5*sec(x)+7=-3\\\\sec(x)=\dfrac{-10}{5} \\\\\dfrac{1}{cos(x)} =-2\\\\cos(x)=-\dfrac{1}{2} \\\\x=120^o\ or\ x=240^o\\

8 0
3 years ago
Read 2 more answers
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