Answer:
Step-by-step explanation:
1) Expand by distributing sum groups.
2) Expand by distributing terms.
3) Collect like terms.
4) Simplify.
Thanks!
- Eddie
okay, so.
it's a rectangle with a nub. We do the area without the nub first. so 8x16 is 128
now, its time for the nub.
6x12-8, that would be 4, so 6x4 is 24+128= 152
So it's B.
Hope i helped Mark brainliest pls
Chad :P
Assume uniformly accelerated motion
Vf = Vo - at => a= [Vo - Vf] / t
Vf = 0, t = 20 s => a = Vo / 20
x = Vot - at^2 / 2
x = Vot - (Vo / 20) * t^2 /2
x = 1775 feet * [1 mile / 5280 feet] = 0.336 mile
t = 20 s
=> 0.336 = 20Vo - Vo(20)^2 /(40) = 20Vo - 10 Vo = 10 Vo
=> Vo = 0.336 /10 = 0.0336 mile /s
Vo = 0.0336 mile/s * 3600 s/h = 120.96 mile / h
Therefore, the car was way over the speed limit.
I hope this helps you. good luck
At equilibrium point, the demand equation is equal to the supply equation.
Given that the <span>demand is Qd = 1500 - 250P, and supply is Qs = 850P, at equilibrium,
1500 - 250P = 850P
850P + 250P = 1500
1,100P = 1,500
P = $1.36
and the equilibruim Q is 1500 - 250(1.36) = 1,159
Therefore, the equilibruim P* is $1.36 and the equilibruim Q* is 1,159.
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