C is the centroid of isoceles triangle ABD with vertex angle <ABD. Does the following proof correctly justify that triangles
ABE and DBE are congruent?
1. It is given that triangle ABD is isoceles, so segment AB is congruent to DB by the definition of isoceles triangle.
2. Triangles ABE and DBE share side BE. so it is congruent to itself by the reflexive property.
3. It is given that C is the centroid of triangle ABD, so segment BE is a perpendicular bisector.
4. E is a midpoint. creating congruent segments AE and DE, by the definition of midpoint.
5. Triangles ABE and DBE are congruent by the SSE postulate.
ANSWER CHOICES:
○ There is an error in line 1; segment AB and BC are congruent.
○ There is an error in line 2; segment BE is not a shared side.
○ There is an error in line 3; segment BE should be a median.
○ The proof is correct.
1. It is given that triangle ABD is isoceles, so segment AB is congruent to DB by the definition of isoceles triangle.
2. Triangles ABE and DBE share side BE. so it is congruent to itself by the reflexive property.
3. It is given that C is the centroid of triangle ABD, so segment BE is a perpendicular bisector.
4. E is a midpoint. creating congruent segments AE and DE, by the definition of midpoint.
5. Triangles ABE and DBE are congruent by the SSE postulate.
ANSWER CHOICES:
○ There is an error in line 1; segment AB and BC are congruent.
○ There is an error in line 2; segment BE is not a shared side.
○ There is an error in line 3; segment BE should be a median.
○ The proof is correct.
1 answer:
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Answer:
Step-by-step explanation:
Given that there are three variables satisfying the equation
Here each x is given to be a positive integer
i.e. solution set for each of the variable can be any integer from 1 to 20 at most.(because if two other integers are 1 each third has to be 20)
Hence solution set can be of the form
If x1 =1, there are 20 solution sets
If x1 =2,there are 19
...
If x1 =20 there is 1 set
Hence total solutions can be