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Lady bird [3.3K]
3 years ago
7

Simplifica y expresa con exponentes positivos

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer:d

Step-by-step explanation:

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Can someone help me find what to do
finlep [7]
An example would be:
Standard:12345678
Expanded: 10000000+2000000+300000+40000+5000+600+70+8
Word: twelve million three hundred forty-five thousand six hundred seventy-eight
5 0
3 years ago
Find the solution set of the inequality
Brilliant_brown [7]

<u>Answer:</u>

\boxed{\textsf{ Hence the solution set is$ \bf{\bigg( \dfrac{33}{4},\infty \bigg) }$}}.

<u>Step-by-step explanation:</u>

A inequality is given to us and we need to find the solution set. So the given inequality to us is ,

  • -4x + 35 >2

\bf\implies -4x + 35 > 2 \\\\\bf\implies -4x > 2-35 \\\\\bf \implies -4x > -33 \\\\\bf \implies x >\dfrac{-33}{-4}\\\\\bf \implies x > \dfrac{33}{4} \\\\\bf\implies \boxed{\pink{\bf x \in \bigg(\dfrac{33}{4}, \infty \bigg) }}

<h3><u>★</u><u> </u><u>Hence </u><u>the </u><u>solution</u><u> </u><u>set </u><u>is </u><u>x </u><u>€</u><u> </u><u>(</u><u> </u><u>3</u><u>3</u><u>/</u><u>4</u><u> </u><u>,</u><u> </u><u>∞</u><u> </u><u>)</u><u>.</u></h3>
3 0
3 years ago
The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50
Natali5045456 [20]

Answer:

(a) See Explanation

(b) \bar x =50 and \sigma_x = 0.8944

(c) The shape is normal

(d) P(\bar x > 55) = 0

Step-by-step explanation:

Given

\mu = \$50 -- mean

\sigma = \$20 --- standard deviation

n=500 --- sample size

Solving (a): The reason we can't determine the probability that an amount to access internet by a household will exceed $55.

The question says that a lot of households pay low rates, but the percentage of the households in this category is not given. This means that it is impossible to determine the shape of the distribution.

Hence, the probability cannot be calculated.

Solving (b): Sample mean and Sample standard deviation

The sample mean estimates the population mean

So:

\bar x =\mu

\bar x =50

The sample standard deviation is calculated as thus:

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{20}{\sqrt{500}}

\sigma_x = \frac{20}{22.36}

\sigma_x = 0.8944

Solving (c): The shape of the distribution.

We have:

n = 500 --- The sample size

According to Central limit theorem, When the sample size is greater than 30, then the shape of the distribution is normal.

<em>Hence, the shape is normal</em>

Solving (d): P(\bar x \ge 55)

Calculate the test statistic (t)

t = \frac{\bar x - \mu}{\sigma}

t = \frac{55 - 50}{0.8945}

t = \frac{5}{0.8945}

t = 5.590

So:

P(\bar x > 55) = P(t > 5.590)

Referencing the z table, we have:

P(t > 5.590) = 0

Hence:

P(\bar x > 55) = 0

5 0
3 years ago
Write 720,080 in expanded form with exponents
Kamila [148]
7 x 10^5
+ 2 x 10^4
+ 0 x 10^3
+ 0 x 10^2
+ 8 x 10^1
+ 0 x 10^0
5 0
3 years ago
Money in a bank triples every 10 years. If $100 is deposited today, what will its value be after 40 years? PLEASE SHOW ME STEP B
LenKa [72]

Answer:

d) $8,100

Step-by-step explanation:

Given information:

  • Money triples every 10 years
  • Initial deposit = $100
  • Number of years invested = 40 years

If the money triples (multiplies by 3) every 10 years,
then in 40 years time it will triple <u>4 times</u>, as 40 ÷ 10 = 4

⇒ Account balance after 40 years = $100 × 3 × 3 × 3 × 3

                                                         = $100 × 3⁴

                                                         = $8,100

<u>Proof</u>

In 10 years time the balance of the account will be:

$100 x 3 = $300

In another 10 years time, the balance of the account will be:

$300 x 3 = $900

In another 10 years time, the balance of the account will be:

$900 x 3 = $2700

In another 10 years time, the balance of the account will be:

$2700 x 3 = $8100

7 0
2 years ago
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