Distance = sqrt(5- -6)^2 + (3- -6)^2)
= sqrt (121 + 81)
= sqrt 202
= 14.21 to nearest hundredth
Answer:
98.1% chance of being accepted
Step-by-step explanation:
Given:
sample size,n=56
acceptance condition= at most 2 batteries do not meet specifications
shipment size=7000
battery percentage in shipment that do not meet specification= 1%
Applying binomial distribution
<h3>P(x)=∑ᵇₐ=₀ (n!/a!(n-a)!)p^a (1-p)^(n-a)</h3>
In this formula, a is the acceptable number of defectives;
n is the sample size;
p is the fraction of defectives in the population.
Now putting the value
a= 2
n=56
p=0.01


=0.56960+0.32219+0.08949
After summation, we get 0.981 i.e. a 98.1% chance of being accepted. As this is such a high chance, we can expect many of the shipments like this to be accepted!
-1, -8
0, -9
1, -10
2, -11
Hope that helps!
Your answer will be choice A.
a = 15.1, b = 23.5, perimeter = 56.6