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lisabon 2012 [21]
3 years ago
9

Add or subtract the polynomials (8x3+3x-2)+(9x2-7+3x-2x3)

Mathematics
2 answers:
crimeas [40]3 years ago
4 0

Answer:

10x^3+9x^2-9

Step-by-step explanation:

8x^3+2x-2+9x^2-7+2x-2x^3 - Combine like terms

10x^3+9x^2-9

LekaFEV [45]3 years ago
3 0

Answer:

\boxed{\boxed{\sf 6x^3+9x^2+6x-9}}

Step-by-step explanation:

\sf \left(8x^3+3x-2\right)+\left(9x^2-7+3x-2x^3\right)

\sf 8x^3+3x-2+9x^2-7+3x-2x^3

Note: If there is a negative sign in front of  parentheses, each term within the expression changes sign.

\Longrightarrow \sf 8x^3+3x-2+9x^2-7+3x-2x^3

Now, we need to organize expression into groups like terms:

\Longrightarrow \sf (8x^3, -2x^3)\: (3x, 3x)\:(-2,-7)

\longmapsto\sf 8x^3-2x^3=6x^3

\longmapsto\sf 3x+3x=6x

\longmapsto\sf -2-7=-9

\boxed{\sf 6x^3+9x^2+6x-9}

_____________________________

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Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

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3 years ago
PLease help will brainlist
tresset_1 [31]

Answer:

7. Option D

9. Option B

10. Option C

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Add these two expressions. (–45t + 53s) and (–3 – 75s + 2t) 65t + 415s – 3 –145t – 115s – 3 –115t + 113s – 3 115t – 415s + 2
serious [3.7K]

Answer:

- 43t - 22s - 3

Step-by-step explanation:

(–45t + 53s) + (–3 – 75s + 2t)

Opening the brackets

-45t + 53s -3 - 75s + 2t

Collecting like terms

-45t + 2t + 53s - 75s -3

Simplify the expression

-43t -22s - 3

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2 years ago
Which is an incorrect rounding for 53.864?<br><br> 54<br> 53.87<br> 50<br> 53.9
Semenov [28]

Answer: 50

Step-by-step explanation:

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