Question

Evaluate 3x² - 4xy + 2y² - 1 for x = - 3 and y = 5

Answer 1

Answer:

$3x^{2} - 4xy + 2y { }^{2} - 1 \\ 3 \times ( - 3) { }^{2} - 4 \times ( - 3) \times 5 + 2 \times 5 {}^{2} - 1 \\ (3 \times 9) - ( - 60) + 50 - 1 \\ 27 + 60 + 50 - 1 \\ 165$

Answer 2

Answer: 136

Substitute -3 for x and 5 for y.

$3x^2 - 4xy + 2y^2 - 1$

$3(-3)^2-4(-3)(5)+2(5)^2-1$

$3(9)-4(-15)+2(25)-1$

$27+60+50-1$

$87+50-1$

$137-1$

$136$

hope this helped!