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Tresset [83]
3 years ago
14

Senna was having a party for 15 friends. She bought 3 jars of

Mathematics
2 answers:
avanturin [10]3 years ago
6 0

Answer:

it is 1.5

Step-by-step explanation:

if u do 4.50÷3 you will get 1.5 so the cost per jar is 1.5

rodikova [14]3 years ago
5 0

Answer:

chicken

Step-by-step explanation:

cuz im like that

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Answer:

15, 8, 66%, 40

Step-by-step explanation:

Hi! ok so in ogive charts its really about finding the corresponding data points and sometimes it's a lot of estimation so these answers may not be exact but they'll be close.

In the image, you'll see a bunch of lines, basically what youre doing is finding the corresponding frequency of the dollars or vice versa.

<em>question a)</em>

50 dollars or less, so the area of 50 dollars and below that.

from the chart we can see that this lines up to around 15 people.

<em>question b)</em>

now this one is a little bit more challenging, but you can use the same process as you did for the first question. so we can see who spent 100 dollars or less. this value is around 42 (just from looking at the graph)

<em>we know if you didn't spend 100 dollars or less, you must have spent more than that. </em>

so take 50-42=8

around 8<u> people</u> spent 100 dollars or more.

<em>question c)</em>

basically the same question as the first but more calculations are involved. from the graph we can see around 33 people spent 80 dollars or less. but the question is asking the percentage. so what percent of 50 (people) is 33.

33/50 = 0.66

around 66%

<em>question d)</em>

80th percentile means less than or equal to 80% of the frequencies/the data. so we first need to find what value that is in terms of frequency.

50 times 0.8 = 40

40 people

now just plot that on the graph (sorry i did it wrong in the image)

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\large\color{lime}\boxed{\colorbox{black}{Answer : - }}

We know that, in ∆ABC,

∠A+∠B+∠C = 180°

But the triangle is right angled at C

ie., ∠C = 90°

Therefore, ∠A+∠B+ 90° = 180°

⇒ ∠A + ∠B = 90°

Therefore, <u>cos(A + B) = cos 90º = 0</u>

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