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sdas [7]
3 years ago
15

Find the unit rate for this situation. Please DO NOT use any extra spaces or

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0
Please GIVE US the problem you want us to answer
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–4.5t49.5t = 40<br> Please help
dlinn [17]

Answer:

t= -0.18

Step-by-step explanation:

Isolate t to get the unknown number:

(-4.5t)(49.5t) = 40

      Multiply (-4.5t)(49.5t):

                     (-4.5t)(49.5t) = -222.75t

      Now, write full equation:

          -222.75t = 40

      Isolate t by dividing -222.75 on both sides:

           \frac{-222.75}{-222.75}t=\frac{40}{-222.75}

      Cancel out left hand side:

            t=\frac{40}{-222.75}

      Simplify your answer:

              t=-0.17957351

      Approximate to 2 decimals:

           t=-0.18

     

5 0
3 years ago
8) plsss helpp meeee!!
konstantin123 [22]

Answer:

  \sqrt[n]{x^a}=x^{a/n}

Step-by-step explanation:

While the "law"

  \sqrt[n]{x^n}=x

may seem more applicable, and may seem to be a special case of the law shown in the answer above, it is not true in general. For example, ...

  \sqrt{x^2}=|x|\ne x \quad\text{for x $

6 0
4 years ago
I need help pls and I will give a 5 star rating and a big thank you comrades.
zhuklara [117]
Answer: B) y=6/11.

To find the horizontal asymptote(s) you must find the limit as x approaches infinity and the limit as x approaches -infinity.

Using L’Hôpital’s rule:
lim x-> infinity (f(x))=6/11.
lim x-> -infinity (f(x))=6/11.
3 0
3 years ago
Read 2 more answers
An item that is on sale for 40% off costs $66. What was the item's regular price?
IRINA_888 [86]
  • <em>Answer:</em>

<em>The regular price was $110</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em />

<em>60% .......... $66</em>

<em>100% ..........$ x</em>

<em>x = 100×66/60</em>

<em>=  6600/60</em>

<em>= $ 110</em>

<em />

<em>Good luck !</em>

7 0
3 years ago
A car completes a journey at an average speed of 40km/h.At what speed must it travel on the return journey if the average speed
nalin [4]
The distance, s = 40t₁ where t₁ is the time to complete the outward journey.
The same distance = vt₂ where t₂ is the time to complete the return journey at speed v.
For the whole journey, 2s=60(t₁+t₂). Therefore s=30(t₁+t₂)=40t₁=vt₂.
30t₁+30t₂=40t₁, 10t₁=30t₂, t₁=3t₂, so s=120t₂=vt₂ and v=120kph.
5 0
3 years ago
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