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2 years ago

Please help :)

Mathematics

1 answer:

IRINA_888 [86]2 years ago

5 0

Answer:

6 hours

Step-by-step explanation:

total: 540 mi

drove motorcycle: 40mph

drove car: 60 mph

11 hours

equation for miles: 540=40x+60y

equation for time: 11=x+y

11=x+y

-x -x

y=-x+11 <---- plug in

540=40x+60(-x+11)

540=40x-60x+660

-660 -660

-120=-20x

/-20 /-20

x=6

6 hours

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Find the GCF and rewrite and equivalent expression using Distributive Property 24-96

yawa3891 [41]

Answer:

GCF(24, 96) = 24

Step-by-step explanation:

Steps:

Prime factorization of the numbers:

24 = 2 × 2 × 2 × 3

96 = 2 × 2 × 2 × 2 × 2 × 3

GCF(24, 96)

= 2 × 2 × 2 × 3

= 24

(hope this helps can i plz have brainlist :D hehe)

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3 years ago

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Step-by-step explanation:

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4 years ago

2x + 7y = 3 = -4y Y =

yaroslaw [1]

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3 years ago

The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in

Marina86 [1]

Answer:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})$

And when we apply the limit we got that:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1$

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

$\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3$

We can express this formula like this:

$\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2$

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

$\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2$

If we operate and we take out the 1/4 as a factor we got this:

$\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}$

We can cancel $n^2$ and we got

$\lim_{n\to\infty} \frac{(n+1)^2}{n^2}$

We can reorder the terms like this:

$\lim_{n\to\infty} (\frac{n+1}{n})^2$

We can do some algebra and we got:

$\lim_{n\to\infty} (1+\frac{1}{n})^2$

We can solve the square and we got:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})$

And when we apply the limit we got that:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1$

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