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Alisiya [41]
3 years ago
11

Alpha Corporation has 1,500 shares of $40 par, 7% cumulative preferred stock, and 2,200shares of 10$ par common stock.Alpha paid

$10,000 in cash dividends including one- year dividends in arrears to preferred stockholders. Camon stockholders received:
Mathematics
1 answer:
Scilla [17]3 years ago
8 0

Answer:

Common stockholders received $1,600.

Step-by-step explanation:

Cumulative preferred stock can be described as a type of preferred stock in which dividends not paid in any year accumulate and has to be paid first in future before common stockholders receive any dividends.

Since the dividends paid in cash by Alpha Corporation includes one- year dividends in arrears to preferred stockholders, this implies that the cumulative preferred stockholders have to paid 2-year dividends, i.e. the one-year arrears plus the current year dividend.

Amount received by common stockholders can be calculated as follows:

Amount of dividend paid by Alpha = $10,000

Annual cumulative preferred stock dividend = 1,500 * $40 * 7% = $4,200

Amount received by cumulative preferred stockholders = Annual cumulative preferred stock dividend * 2 years = $4,200 * 2 = $8,400

Amount received by common stockholders = Amount of dividend paid by Alpha - Amount received by cumulative preferred stockholders = $10,000 - $8,400 = $1,600

Therefore, common stockholders received $1,600.

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5 0
3 years ago
Please help me and answer correctly!
LenKa [72]
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3 0
3 years ago
You have a wire that is 38 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
Drupady [299]

Answer:16.71 cm

Step-by-step explanation:

Given

Length of wire L=38 cm

One piece is bent in the form of square and another in the form of circle

let x be the length of circle

therefore length of square side \frac{38-x}{4}

A=total area of square and circle

radius of circle r=\frac{x}{2\pi }

area of circle A_c=\pi r^2=\pi \times (\frac{x}{2\pi })^2

Area of square A_s=(\frac{38-x}{4})^2

A=\pi \times (\frac{x}{2\pi })^2+(\frac{38-x}{4})^2

To get the minimum value of A we get

\frac{\mathrm{d} A}{\mathrm{d} x}=\frac{2x}{4\pi }-\frac{2(38-x)}{16}

\frac{\mathrm{d} A}{\mathrm{d} x}=0

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Therefore circumference of circle

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8 0
3 years ago
Find the range of m=180-3c if the domain is {-3, 0, 3}
riadik2000 [5.3K]
Plug in each value for c.
m = 180 - 3(-3) = 189
m = 180 - 3(0) = 180
m = 180 - 3(3) = 171

Range {171, 180, 189}
6 0
3 years ago
For the following system, use the second equation to make a substitution for y in the first equation. 2x + y = 5 y + 3 = 2x
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If y equals 2x - 3 in the second equation, than subsitute it in for y in the first.
2x + 2x - 3 = 5
4x - 3 = 5
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x = 2 and y = 1

6 0
3 years ago
Read 2 more answers
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