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4 years ago

NEED HELP !!!!!Write an equation for the following proportional relationships. ( x/y ) a. 1/2.5 b . 6/18 C. 5/22.5 d. 4/17

Mathematics

1 answer:

lutik1710 [3]4 years ago

6 0

Answer:

x=21

Step-by-step explanation:

add 11 and 11

then you will get 21

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What is the product of the rational expressions shown below? Make sure your

VikaD [51]

Answer:

5x / (x - 4)

Step-by-step explanation:

(x + 1)/(x - 4) • 5x/(x + 1)

Method 1:

Cancel out x + 1

Leaving 5x/(x - 4)

Method 2:

(x + 1)/(x - 4) • 5x/(x + 1)

Multiply numerator and denominator separately

= 5x(x + 1) / (x - 4)(x + 1)

Cancel out (x + 1) in the numerator and (x + 1) in the denominator

= 5x / (x - 4)

Therefore,

(x + 1)/(x - 4) • 5x/(x + 1) = 5x / (x - 4)

7 0

3 years ago

Thanks for helping with calculus

allochka39001 [22]

Integrating $f(x)$ gives

$g(x)=\displaystyle\int f(x)\,\mathrm dx=C+\sum_{n=0}^\infty\frac{a_n}{n+1}x^{n+1}$

Notice that $x=0$ forces all terms in the sum to be 0, so that

$g(0)=C=5$

and hence

$g(x)=\displaystyle5+\sum_{n=0}^\infty\frac{a_n}{n+1}x^{n+1}$

making the first option correct.

3 0

4 years ago

genetic experiment with peas resulted in one sample of offspring that consisted of green peas and yellow peas. a. Construct a %

Andreas93 [3]

Complete Question

A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?

Answer:

The 95% confidence interval is $0.2392 < p < 0.3108$

No, the confidence interval includes 0.25, so the true percentage could easily equal 25%

Step-by-step explanation:

From the question we are told that

The total sample size is $n = 432 + 164 =596$

The number of offspring that is yellow peas is $y = 432$

The number of offspring that is green peas is $g = 164$

The sample proportion for offspring that are yellow peas is mathematically evaluated as

$\r p = \frac{ 164 }{596}$

$\r p = 0.275$

Given the the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100 - 95)\%$

$\alpha = 5\% = 0.0 5$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p )}{n} }$

=> $E = 1.96 * \sqrt{\frac{0.275 (1- 0.275 )}{596} }$

=> $E = 0.0358$

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

=> $0.275 - 0.0358 < p < 0.275 + 0.0358$

=> $0.2392 < p < 0.3108$

6 0

3 years ago

F) 234x +(234x)⁰ (x0)

Murrr4er [49]

Answer:

the answer is 0

Step-by-step explanation:

because anything multiply by 0 is 0.

Can make me the brainliests answerer?Please

6 0

2 years ago

Please help if you can. I will give Brainiest to best answer. This question is a Calculus/Trigonometry question. I ask that you

Ierofanga [76]

7 is incorrect. The answer should be -4. Here's how I'd derive it:

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

With $\pi$ , we should expect $\cos x$ . If $\tan x=\dfrac8{15}$ , then

$\sec x=-\sqrt{1+\tan^2x}=-\dfrac{17}{15}\implies\cos x=-\dfrac{15}{17}$

Also,

$\pi$

so we should expect $\tan\dfrac x2$ and

$\tan\dfrac x2=-\sqrt{\dfrac{1-\cos x}{1+\cos x}}=-4$

You seem to be taking

$\tan\dfrac x2=\dfrac{1+\cos x}{-\sin x}$

but this is not an identity.

###

8 is incorrect. Just a silly mistake, you swapped the order of the terms in the numerator. It should be

$\dfrac{\sqrt6-\sqrt2}4$

###

9. Use the identity from (7). $\dfrac{7\pi}{12}$ lies in the second quadrant, so

$\tan\dfrac{7\pi}{12}=-\sqrt{\dfrac{1-\cos\frac{7\pi}6}{1+\cos\frac{7\pi}6}}=-\sqrt{7+4\sqrt3}=-2-\sqrt3$

###

12.

$\dfrac{\cot x-1}{1-\tan x}=\dfrac{\frac{\cos x}{\sin x}-1}{1-\frac{\sin x}{\cos x}}$

$=\dfrac{\cos x(\cos x-\sin x)}{\sin x(\cos x-\sin x)}$

$=\dfrac{\cos x}{\sin x}$

$=\dfrac{\csc x}{\sec x}$

###

13.

$\dfrac{1+\tan x}{\sin x+\cos x}=\dfrac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}$

$=\dfrac{\cos x+\sin x}{\cos x(\sin x+\cos x)}$

$=\dfrac1{\cos x}$

$=\sec x$

###

14.

$\sin2x(\cot x+\tan x)=2\sin x\cos x\left(\dfrac{\cos x}{\sin x}+\dfrac{\sin x}{\cos x}\right)$

$=2\sin x\cos x\dfrac{\cos^2x+\sin^2x}{\sin x\cos x}$

$=2$

###

15.

$\dfrac{1-\tan^2\theta}{1+\tan^2\theta}=\dfrac{1-\frac{\sin^2\theta}{\cos^2\theta}}{1+\frac{\sin^2\theta}{\cos^2\theta}}$

$=\dfrac{\cos^2\theta-\sin^2\theta}{\cos^2\theta+\sin^2\theta}$

$=\cos2\theta$

3 0

3 years ago

NEED HELP !!!!!Write an equation for the following proportional relationships. ( x/y ) a. 1/2.5 b . 6/18 C. 5/22.5 d. 4/17​

NEED HELP !!!!!Write an equation for the following proportional relationships. ( x/y ) a. 1/2.5 b . 6/18 C. 5/22.5 d. 4/17